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Create pressure drop across components in a system |
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June 20, 2019, 15:25 |
Create pressure drop across components in a system
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#1 |
New Member
Bram
Join Date: Apr 2019
Posts: 13
Rep Power: 7 |
Hello All,
I'm new to StarCCM+. I'm trying to study flow through a piping system. Aim is to study the flow distribution in the system. The piping system contains multiple components attached to it. These components have complicated geometries. I'm not particularly interested in the flow distribution within the components. I know the pressure drop that each of these added components create. Is it possible to replace them with simple geometries and add the pressure drop they create. I did some search and I found that periodic boundary condition could be a way to do it. Any advise on defining the geometry and the corresponding boundary conditions would be really helpful. Thank you. |
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June 21, 2019, 07:34 |
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#2 | |
Senior Member
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Quote:
You can simply create a small region as a porous region. This is common practice for such cases. Get the pressure drop across components to be replaced. From pressure drop you can calculate porous coefficients. Refer user guide for this. And then insert a porous region. Hope this helps. |
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June 21, 2019, 10:57 |
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#3 |
Senior Member
Matt
Join Date: Aug 2014
Posts: 947
Rep Power: 18 |
You could also use a porous baffle interface if you are looking for an instantaneous change, rather than one that happens over some length along the flow path..
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June 21, 2019, 11:16 |
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#4 |
New Member
Bram
Join Date: Apr 2019
Posts: 13
Rep Power: 7 |
Thanks for guiding me. Really appreciate it. Will get back after I setup the case .
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July 8, 2019, 15:15 |
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#5 |
New Member
Bram
Join Date: Apr 2019
Posts: 13
Rep Power: 7 |
Hey Guys,
I used your advice and was successfully able to get the setup running. However, I have doubt which came up now. I know it's really fundamental, your advise would be really helpful. 1) I used dP/L vs velocity plot to obtain the inertial and viscous coefficients. I’ve used second degree polynomial curve fitting (ax^2+bx). What is length that should be considered to calculate dp/L. Is it the dimension of the actual component or the geometry of the porous media that I'm using for my setup. dP – Pressure drop, L – length. Thank you. |
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July 8, 2019, 15:17 |
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#6 |
Senior Member
Matt
Join Date: Aug 2014
Posts: 947
Rep Power: 18 |
L will be the streamwise width of your porous region, assuming you have 3D porous regions and not 2D baffles.
So if you have a rectangular porous region of w x h x t where flow moves along t, you would set L = t. Make sure to use fundamental units too. Pa, m and m/s so that your units work out to a = kg/m^4 and b = kg/m^3-s |
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July 8, 2019, 15:21 |
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#7 | |
New Member
Bram
Join Date: Apr 2019
Posts: 13
Rep Power: 7 |
Quote:
Sincerely appreciate your help . |
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July 9, 2019, 08:14 |
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#8 |
Member
Yogesh Nalam
Join Date: Sep 2012
Location: München, Germany
Posts: 54
Rep Power: 14 |
I am not very sure. But you have to give resistance coefficients along coordinate axis directions, so I think bends might change your desired flow.
Instead you could create a straight porous region and the bend you can model it as slip wall condition. |
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July 9, 2019, 16:11 |
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#9 | |
New Member
Bram
Join Date: Apr 2019
Posts: 13
Rep Power: 7 |
Quote:
Thanks again! |
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July 9, 2019, 16:19 |
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#10 |
Senior Member
Matt
Join Date: Aug 2014
Posts: 947
Rep Power: 18 |
You can assign an axisymmetric tensor and define on axis and cross-axis values. Then use interpolateDirection() to get a field function that assigns a vector field that is parallell to the closest wall. Set axisymmetric tensor axis to your calculated values and set off-axis properties to be anywhere from 10x to 100x your on-axis properties. The flow will follow the bends and should result in (close to) the expected DP.
The value L will be the integrated path length along your bent section. |
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July 9, 2019, 16:30 |
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#11 | |
New Member
Bram
Join Date: Apr 2019
Posts: 13
Rep Power: 7 |
Quote:
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July 11, 2019, 12:37 |
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#12 |
New Member
Bram
Join Date: Apr 2019
Posts: 13
Rep Power: 7 |
Hello All,
I tried the asymmetric tensor suggest by @fluid23. But the pressure drop values are really high. One thing I noted is that my inertial resistance is one order of magnitude higher than my viscous resistance. Is this trend normal ? As mentioned earlier I used Ax^2+Bx for curve fitting, where A is my inertial resistance and B is my viscous resistance. Thank you. |
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