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Turbulence Model and Inflation layers OpenFOAM |
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January 9, 2024, 20:14 |
Turbulence Model and Inflation layers OpenFOAM
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#1 |
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Anurag
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Hi everyone,
I am a bit confused. For ke turbulence model y+ should be around 30, but do we need to give inflation layers? I am modeling fully turbulent partially-filled pipe flow using interFOAM. If without inflation layers I can get y+ around 30 is it not sufficient? I am a bit confused. ALso for komega, y+ should be around 1, so for that is inflation layer required? Any help is greatly appreciated. Thanks |
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January 9, 2024, 21:16 |
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#2 | |
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January 9, 2024, 21:19 |
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#3 | |
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Anurag
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Thanks. |
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January 10, 2024, 04:37 |
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#4 | |
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Joern Beilke
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You either use wall functions and an Y+ of 30 .. 200 OR you use a low-reynolds approach, where you resolve the boundary layer with a suitable fine mesh. |
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January 10, 2024, 05:54 |
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#5 |
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The boundary layer is composed of:
- Inner layer: viscous sublayer + buffer layer + logarithmic layer - Outer layer: from the edge of the logarithmic layer to the edge of the boundary layer itself. It does not matter if you're using wall functions or resolving the viscous sublayer; you must have a sufficient number of cells that cover the entire boundary layer (inner layer + outer layer). Imagine this scenario: You use a mesh with a first cell center from the wall that satisfies y+ < 1 but with a growth rate of 5.0. Yes, the y+ is satisfied, but certainly, there will be no sufficient number of cells that will cover the entire BL. The bottom line: You must use a proper y+ with a growth rate that guarantees that you sufficiently resolve the entire boundary layer.
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January 10, 2024, 13:58 |
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#6 | |
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Anurag
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Many Thanks |
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January 10, 2024, 14:33 |
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#7 |
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Arjun
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I would want first point at Yplus of 30. Just where the buffer layer ends.
Then i would use law of wall from here. If i have to have grid points starting from yplus of 1 (or 5) to some points in 5 to 30 range then then some points after that then i do not really need any wall law. Everything is pretty much resolved for shear rate. |
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January 10, 2024, 15:22 |
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#8 |
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Anurag
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What I can tell is, for internal flows wall function can do the job to resolve the BL but for external flows where drag is very important we cannot rely on wall functions-we have to resolve the BL by making a very fine mesh physically.
Yes growth rate is very important to resolve the BL accurately. I hope I am correct. |
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January 10, 2024, 15:26 |
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#9 |
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Anurag
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I am a bit confused about the y+value that I will take while using ke and komega models? is it around 30 and 1 respectively for pipe flow?
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January 10, 2024, 15:45 |
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#10 | |
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k-epsilon is not a single turbulence model, there are hundreds of these models and you should know that what is referred to as k-epsilon is the standard k-epsilon model which is a high Reynolds number model. Be careful though that High Reynolds number name here is misleading and has nothing to do with the Reynolds number of your object. A high-Re model is a model that can't be integrated all the way to the wall and it requires using Wall Functions. However, there are versions of the k-epsilon models that can be used all the way down to the wall (achieved by using damping functions). You guessed it, these models are termed "Low-Re models". (advice: never use low-Re kepsilon models, they suffer from a number of numerical issues and should be avoided all together). On the other hand the k-omega family are low-Re models by construction (they are valid all the way down to the wall) which means that they can be used without wall functions. Hence they require y+ to be less than 5. But it also important to keep in mind that they can be used with wall functions as well. Conclusion. - The standard k-epsilon model is a High-Re turbulence model and requires the usage of wall functions (y+ must be greater than 30). - The k-Omega model is a low-Re model that can be used with and without wall functions. I hope this helps.
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January 10, 2024, 16:06 |
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#11 | |
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Arjun
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You are correct. In separating flows there can be issues so its better to resolve the boundary layer if possible. (then we do not really need wall functions). |
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January 10, 2024, 17:00 |
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#12 |
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Anurag
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Hi arjun and NotOverUnderated,
Thanks, What I understood by reading some lectures is- if I can resolve the BL by a very fine mesh, then no need of wall functions. But to save CFD time, we use a wall function for certain flow types near the wall without resolving the mesh. In this case, there is no need of inflation layers and growth rate. |
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