|
[Sponsors] |
April 17, 2019, 11:30 |
Calculation of turbulence length scale
|
#1 |
Member
Joe lee
Join Date: Nov 2018
Posts: 59
Rep Power: 8 |
In the motorBike tutorial case, the turbulence kinetic energy (k) and specific turbulence dissipation (omega) are 0.24 and 1.78 respectively. Using https://www.cfd-online.com/Tools/turbulence.php, we can find that the turbulence length scale is about 0.275m. However, in https://en.wikipedia.org/wiki/Turbulence_kinetic_energy, the turbulence length scale is calculated using:
Code:
l = 0.07*L In this case, the motorBike has a characteristic length of 1.42m. So its turbulence length scale should be 1.42*0.07 = 0.0994m. How is the turbulence length scale of the motorBike calculated? And if I need to calculate one for my own model, should I stick with the equation l=0.07*L? Thanks a lot. |
|
April 20, 2019, 11:33 |
|
#2 |
Member
Joe lee
Join Date: Nov 2018
Posts: 59
Rep Power: 8 |
Does anyone know how to calculate it?
|
|
April 23, 2019, 04:51 |
|
#3 |
Senior Member
Robert
Join Date: May 2015
Location: Bremen, GER
Posts: 292
Rep Power: 12 |
The characteristic length is something strange. It changes from case to case, from author to author and is seems the most important factor is to be consistent with what you call your characteristic length throughout your work. For channel or duct flows L is the hydraulic diameter.
I use to calculate the turbulent length scale as , which, if i'm not mistaken, is a formula if found somewhere on this website. The turbulent kinetic energy i calculate as with I, the turbulence intensity being and Re the Reynolds number. At which point we are back at the question of "what is the characteristic length?".
__________________
If you liked my answer to your question, please consider leaving a "Like" in return |
|
April 23, 2019, 06:31 |
|
#4 |
Member
Joe lee
Join Date: Nov 2018
Posts: 59
Rep Power: 8 |
Quote:
Also, the equation you gave is using the hydraulic diameter, so it seems referring to internal flow. Yet, the motorBike tutorials is an external flow, so I am not sure if the equation is applicable or not. |
|
April 23, 2019, 06:38 |
|
#5 | |
Super Moderator
Tobias Holzmann
Join Date: Oct 2010
Location: Bad Wörishofen
Posts: 2,711
Blog Entries: 6
Rep Power: 52 |
Maybe you were referring to my thread: turbulent length scale
Quote:
__________________
Keep foaming, Tobias Holzmann |
||
April 23, 2019, 07:03 |
|
#6 | |
Member
Joe lee
Join Date: Nov 2018
Posts: 59
Rep Power: 8 |
Quote:
|
||
April 23, 2019, 14:40 |
|
#7 |
Senior Member
Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
Posts: 5,761
Rep Power: 66 |
What's important is the value of k and epsilon or k and omega. Sometimes this is calculated from a turbulence length scale (if it is known), many times it is not.
k, epsilon/omega, and the length scale are a property of the flow, not necessarily of the geometry. The l=0.038L is an empirical correlation coming from pipe flows, and only valid for the centerline. I forget the exact reference, but it is a popular turbulence text (probably something like Schlicting or Batchelor or something). The characteristic length L is either the pipe diameter or hydraulic diameter of the pipe or pipe-like thingy. You cannot just put in any arbitrary length here, like the length of the bike. The flow arriving coming at the bike is not a pipe flow... So you should not be using this method to estimate k and epsilon anyway. The real question is where does 0.24 and 1.78 come from, and that I'm not sure either. It is a valid question with a non-trivial answer. Being a flow property, it requires you to know something about the flow. Turbulence boundary conditions are not so straightforward. |
|
April 23, 2019, 15:25 |
|
#8 | |
Member
Joe lee
Join Date: Nov 2018
Posts: 59
Rep Power: 8 |
Quote:
1. Typical wind tunnel (front=inlet; back=outlet; all other four faces=wall) 2. Front=inlet; bottom=wall; all other faces=outlet So for the preferred case, what parameter and formula is suitable for calculating turbulence length scale? Thank you very much! |
||
April 26, 2019, 14:30 |
|
#9 |
Member
Joe lee
Join Date: Nov 2018
Posts: 59
Rep Power: 8 |
Actually I am wondering how to obtain the turbulence length scale in the motorBike tutorial. That is not an internal flow, and has no hydraulic diameter, so how can we estimate the length scale?
|
|
April 27, 2019, 06:29 |
|
#10 |
Super Moderator
Tobias Holzmann
Join Date: Oct 2010
Location: Bad Wörishofen
Posts: 2,711
Blog Entries: 6
Rep Power: 52 |
Hi,
that is not correct. The motorbike tutorial has an hydraulic diameter and it is simply the projected area and its perimeter. I just refer to József Nagy's christmas community competition. Here, we analyzed the 'Suzanne's head' (Blender). The hydraulic diameter can be estimated as the projected area and its perimeter in that case too. However, I never investigated into the motorbike tutorial and its values for k and epsilon. At the end we should always keep in mind, that the turbulence modelling is an approach to handle and simplify the complexity of the turbulence itself. Therefore, the values for k and epsilon / omega should be approximately in a good range but at the end there are so many other parameters that influences the results too - such as discretization schemes, mesh quality, and so on and so on.
__________________
Keep foaming, Tobias Holzmann |
|
April 27, 2019, 08:02 |
|
#11 | |
Member
Joe lee
Join Date: Nov 2018
Posts: 59
Rep Power: 8 |
Quote:
And one more question, is the turbulence length scale same as the characteristic length used in calculation of drag coefficient? Thanks a lot! |
||
February 19, 2020, 13:27 |
|
#12 |
New Member
Andrea Stedile
Join Date: Feb 2020
Posts: 11
Rep Power: 6 |
Hi Joe, have you ever found it out? I'm in the same situation.
|
|
February 19, 2020, 18:34 |
|
#13 |
Senior Member
Herpes Free Engineer
Join Date: Sep 2019
Location: The Home Under The Ground with the Lost Boys
Posts: 931
Rep Power: 13 |
might help this function object?: turbulenceFields.
__________________
The OpenFOAM community is the biggest contributor to OpenFOAM: User guide/Wiki-1/Wiki-2/Code guide/Code Wiki/Journal Nilsson/Guerrero/Holzinger/Holzmann/Nagy/Santos/Nozaki/Jasak/Primer Governance Bugs/Features: OpenFOAM (ESI-OpenCFD-Trademark) Bugs/Features: FOAM-Extend (Wikki-FSB) Bugs: OpenFOAM.org How to create a MWE New: Forkable OpenFOAM mirror |
|
April 9, 2020, 06:46 |
iChrome Calculator
|
#14 |
New Member
Jasper Eerdekens
Join Date: Apr 2020
Location: Brussels
Posts: 1
Rep Power: 0 |
I found a calculator in the following link: http://ichrome.com/blogs/archives/342
This calculates the Turbulence length scale with the formula: l=0.07*L Below in the "HOW TO USE" it is stated that L equals: - pipe's diameter - or a vehicle's length Does anyone think this is incorrect? Best regards. |
|
May 4, 2020, 19:39 |
|
#15 |
New Member
Victor J. Pugliese Manotas
Join Date: Sep 2018
Location: Lubbock, TX
Posts: 1
Rep Power: 0 |
In my case, I simulated slug flow in a pipe, and I used the grid size as turbulent length to calculate the boundary conditions for interFOAM - LES- Smagorinsky solver, and got good results compared with experiment results.
According the Large Eddy Simulation (LES) theory, we need to estimate the turbulence inside the cell (the unresolved scale). |
|
April 21, 2022, 11:44 |
|
#16 | |
Senior Member
Sakun
Join Date: Nov 2019
Location: United Kingdom
Posts: 152
Rep Power: 7 |
Quote:
Hi, can you explain bit further about grid size value for turbulent length scale ? much appreciate |
||
Tags |
calculation, motorbike, turbulence length scale |
|
|
Similar Threads | ||||
Thread | Thread Starter | Forum | Replies | Last Post |
wrong SU2 calculation for lift and drag coefficient for NAC4421 | mechy | SU2 | 7 | January 9, 2017 06:18 |
Interface treatment in turbulent model and its length scale. | paka | OpenFOAM Running, Solving & CFD | 0 | February 15, 2014 03:02 |
turbulence intensity and length scale | mohammad | FLUENT | 0 | January 7, 2012 09:57 |
Calculation for Turbulent Length Scale | aqib | CFX | 4 | December 14, 2010 06:24 |
calculation of eddy length scale | nathalie | FLUENT | 0 | February 2, 2009 13:05 |