|
[Sponsors] |
February 20, 2017, 13:05 |
2D cylinder Turbulent Flow
|
#1 |
Member
Fredi Cenci
Join Date: Dec 2016
Posts: 38
Rep Power: 9 |
p { margin-bottom: 0.25cm; line-height: 120%; } p { margin-bottom: 0.25cm; line-height: 120%; }
Hello guys, I am simulating a turbulent flow around a circular cylinder. I ran 28500 steps already and the lift doesn’t converge to the experimental results. Some information: Turbulence Model = k-w SST Re = 60000 D = 1 m nu = 1.5e-5 m2/s I = 0.5% Turbulent mixing length: D*0.07 = 0.07 m rho = 1.225 U = 0.9 k = 1.5*(U*I)² = 0,00003 omega = Cu^(-1/4) *k^(0.5)/T length = 0,1437 I have meshed with blockMesh and a have a pretty refined mesh near to the cylinder y+ < 1. The courant number is also generally bellow 1 (I had to reduce the time step to 0.002) . Look at the graphs. Can someone look at my schemes and solution files? Give some tips about my set up and etc… I will try a 3 dimensional cylinder after this.. Link with the simulation (compacted with .tar): https://www.dropbox.com/s/2y5kyja3gu...on.tar.gz?dl=0 Thanks a lot. |
|
February 21, 2017, 01:09 |
|
#2 |
Senior Member
Uwe Pilz
Join Date: Feb 2017
Location: Leipzig, Germany
Posts: 744
Rep Power: 15 |
> pretty refined mesh near to the cylinder y+ < 1.
As far as I understand the problem: The k-eps model makes some assumptions for the innermost layer, the laminar Prandtl layer. This layer reachces until around y+=30. Therefore the innermost nodal layer should be in this range (and not much finer).
__________________
Uwe Pilz -- Die der Hauptbewegung überlagerte Schwankungsbewegung ist in ihren Einzelheiten so hoffnungslos kompliziert, daß ihre theoretische Berechnung aussichtslos erscheint. (Hermann Schlichting, 1950) |
|
February 21, 2017, 01:18 |
|
#3 |
Member
Fredi Cenci
Join Date: Dec 2016
Posts: 38
Rep Power: 9 |
Thanks for your reply,
So, I am not using wall functions. I am solving the viscous layer, as far as I know I should put a cell in Y+<1 so I can solve the viscous layer. Are you saying the problem is that I have too much cells near to the wall in some locations? It is hard to keep a constant number for Y+ once the velocity changes a lot around the cylinder. I am using k-omega SST.. |
|
February 21, 2017, 02:08 |
|
#4 |
Senior Member
Mikko
Join Date: Jul 2014
Location: The Hague, The Netherlands
Posts: 243
Rep Power: 13 |
If you look at your experimental data, there is a sudden decrease in drag coefficient at around Re=300 000. This means that the boundary layer is mostly laminar below Re=300 000 and turbulent above it. Common turbulence models (k-omega SST, k-eps etc.) assume always turbulent boundary layer and therefore you cannot use them with low Reynolds numbers. So, try switching off the turbulence model.
The mean lift coefficient for symmetric bodies such as cylinder is zero and therefore in your experimental data they give the root mean square of the lift. |
|
February 21, 2017, 09:32 |
|
#5 |
Member
Fredi Cenci
Join Date: Dec 2016
Posts: 38
Rep Power: 9 |
Yehh, I am gonna try switch off the turbulence. I thought it was turbulent already because this picture (also from the Sumer book "Hydrodynamics around cylindrical structures").
Thank you! I will post the results when I finish it. |
|
February 21, 2017, 11:51 |
|
#6 | |
Member
Fredi Cenci
Join Date: Dec 2016
Posts: 38
Rep Power: 9 |
Quote:
The lift and drag curves are better. Cd (mean) = 1.5... experimental is 1.25 Cl (peak) = 1.67... experimental is 0.4 r.m.s.. 0.4/0.7071 = 0.56 I don't know why the lift has such a big error... I checked the Diameter (D=1), reference area (A = 1) and reference length (L=1), everything looks fine. Any Idea? I really appreciate the support. |
||
February 22, 2017, 01:24 |
|
#7 |
Senior Member
Uwe Pilz
Join Date: Feb 2017
Location: Leipzig, Germany
Posts: 744
Rep Power: 15 |
> I don't know why the lift has such a big error.
As you can see in your force coefficient diagrams the solution is not stable, you have a transient case. The coefficents are changing forever. The best thing you may calculate is a time averaged value of it.
__________________
Uwe Pilz -- Die der Hauptbewegung überlagerte Schwankungsbewegung ist in ihren Einzelheiten so hoffnungslos kompliziert, daß ihre theoretische Berechnung aussichtslos erscheint. (Hermann Schlichting, 1950) |
|
February 22, 2017, 05:13 |
|
#8 |
Senior Member
Mikko
Join Date: Jul 2014
Location: The Hague, The Netherlands
Posts: 243
Rep Power: 13 |
Try first copying fvScheme and fvSolution dictionaries from a tutorial case which uses pisoFoam. For instance, I think you should not use under relaxation factors with pisoFoam. Also, you cannot calculate rms from the mean value straightaway. Your mesh could be improved but probably it's good enough. I would start first with lower Reynolds number to minimize the effect of turbulence.
|
|
February 22, 2017, 07:46 |
|
#9 | |
Member
Fredi Cenci
Join Date: Dec 2016
Posts: 38
Rep Power: 9 |
Quote:
I got the schemes and solution from a tutorial of a cylinder with lower Reynolds (Re = 100). Yes I added Relaxation Factors because I was using k-omega SST but then I switched off the turbulence and I forgot to remove them. =) And Yes, I probably should run more steps.. I will do it! Tutorial: https://www.youtube.com/watch?v=ylZQXiEdYYo Thanks for the comments =) |
||
September 24, 2017, 12:50 |
|
#10 |
New Member
Miad Al Mursaline
Join Date: Nov 2016
Posts: 15
Rep Power: 10 |
Can you please tell me where you got experimental data for turbulent flow around cylinders?
|
|
September 27, 2017, 08:38 |
|
#11 |
Member
Fredi Cenci
Join Date: Dec 2016
Posts: 38
Rep Power: 9 |
||
September 27, 2017, 10:08 |
|
#12 |
Senior Member
Uwe Pilz
Join Date: Feb 2017
Location: Leipzig, Germany
Posts: 744
Rep Power: 15 |
__________________
Uwe Pilz -- Die der Hauptbewegung überlagerte Schwankungsbewegung ist in ihren Einzelheiten so hoffnungslos kompliziert, daß ihre theoretische Berechnung aussichtslos erscheint. (Hermann Schlichting, 1950) |
|
September 28, 2017, 14:10 |
|
#13 |
New Member
Miad Al Mursaline
Join Date: Nov 2016
Posts: 15
Rep Power: 10 |
Thank you for the information
|
|
December 5, 2017, 19:10 |
|
#14 |
Member
Leonardo
Join Date: Nov 2017
Posts: 37
Rep Power: 9 |
||
|
|
Similar Threads | ||||
Thread | Thread Starter | Forum | Replies | Last Post |
k-omega SST simulation of turbulent flow around a circular cylinder | DanM | OpenFOAM Running, Solving & CFD | 17 | October 13, 2016 14:29 |
Drag force coefficient too high for a flow past a cylinder using komega sst | Scabbard | OpenFOAM Running, Solving & CFD | 37 | March 21, 2016 17:16 |
Flow over 2D Cylinder, Laminar and Turbulent | Tsr63 | FLUENT | 5 | November 13, 2014 13:13 |
Compare the pressure of potential flow and a turbulent case of cylinder | ooo | OpenFOAM Running, Solving & CFD | 0 | August 2, 2013 08:25 |
Incompressible, Unsteady Cylinder Flow | startingcfd | Main CFD Forum | 1 | March 15, 2011 02:12 |