[sharonyue]

Hi guys,

I have a confusion, for example, I have 100 same volScalarField, T1, T2, ... T100.

I can create them by:

volScalarField T1
    (
        IOobject
        (
            "T1",
            runTime.timeName(),
            mesh,
            IOobject::NO_READ,
            IOobject::NO_WRITE
        ),
        mesh,
        dimensionedScalar("zero", dimensionSet(0, 0, 1, 0, 0), 0.0)
    );

Also I can create them by:

volScalarField T2(T1);

volScalarField T3(T1);

...

Is there any difference on this? from the memory consumption and computational speed?

Best,


/*******************************************/

Okay, I got it, even with the second method, T2 is also registered from objectRegistry implicitly.

[hk318i]

You conclusion is right.
You are creating the same type using two different constructors. First one is more explicit and the second one is a typical copy constructor. Therefore all the copied instances are registered to the same mesh and have the same field size.