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decomposePar - view how mesh is divided up

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Old   June 1, 2020, 16:25
Default decomposePar - view how mesh is divided up
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Conor
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Hi Guys,

Can anyone tell me if it is possible to view how the mesh is partitioned after using decomposePar? I am using the scotch function.

I know that the points and neighbor patch info are divided into their respective processor files. Is it possible to visualize the decomposition?

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Conor
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Old   June 2, 2020, 06:46
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yes,
after decomposing, open your .foam-file with paraview.
for case type, under properties, select: decomposed case.

you should be able to see boundaries in your internal mesh.
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Old   June 2, 2020, 12:15
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Quote:
Originally Posted by geth03 View Post
yes,
after decomposing, open your .foam-file with paraview.
for case type, under properties, select: decomposed case.

you should be able to see boundaries in your internal mesh.
Right, then you can either reduce the opacity a little bit or just show the geometry as "wireframe".
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Old   June 6, 2020, 06:52
Default processorField function object
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Fumiya Nozaki
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You can use processorField function object to visually check how your mesh is decomposed.
https://www.openfoam.com/documentati...d.html#details

Best regards,
Fumiya
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Old   June 6, 2020, 09:29
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I think the following link is more appropriate for a user guide: https://www.openfoam.com/documentati...ssorField.html (the above is the API guide).

PS: By the way, I am one your followers who were trying to promote your page (can find your surname below) .
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Old   June 6, 2020, 10:31
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Fumiya Nozaki
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Hi HPE,

Thank you for your correction and the link to my blog!

Best regards,
Fumiya
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Old   June 26, 2020, 13:32
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decomposePar -cellDist -dry-run
if my memory serves me.
Should be fast, since it only writes the cell distribution (as a serial field) but doesn't write the processor files.
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