CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > General Forums > Main CFD Forum

difference between isotropic and homogeneous in turbulence

Register Blogs Community New Posts Updated Threads Search

Like Tree17Likes
  • 2 Post By ganesh
  • 4 Post By Jade M
  • 1 Post By simulationman
  • 8 Post By MaRaz
  • 1 Post By ndestrad
  • 1 Post By FMDenaro

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   October 28, 2010, 22:13
Default difference between isotropic and homogeneous in turbulence
  #1
New Member
 
Join Date: Feb 2010
Posts: 12
Rep Power: 16
dut_thinker is on a distinguished road
Some literature wrote that 'One might argue that no real turbulent flow is isotropic or even homogeneous in the large scales.'
It sounds that homogeneous is stricter than isotropic!
SO who can give me any hints about the difference between isotropic and homogeneous?

Any comments will be appreciated.
dut_thinker is offline   Reply With Quote

Old   October 29, 2010, 02:10
Default
  #2
Member
 
ganesh
Join Date: Mar 2009
Posts: 40
Rep Power: 17
ganesh is on a distinguished road
Dear Dut_thinker,

Isotropic turbulence demands that there is no mean shear, rotation or buoyancy effects in the flow as this can lead to anisotropy. Homogeneous turbulence is indicative of the fact that there are no mean flow gradients. In a more simpler sense, homogeneity deals with invariance in translation, isotropy deals with invariance in rotation. Take a look at MIT OCW notes on turbulence if you wish for more information.

Regards,

Ganesh
kcavatar and vivek05 like this.
ganesh is offline   Reply With Quote

Old   October 29, 2010, 14:26
Default
  #3
f-w
Senior Member
 
f-w's Avatar
 
Join Date: Apr 2009
Posts: 159
Rep Power: 17
f-w is on a distinguished road
http://books.google.com/books?id=HZs...page&q&f=false
f-w is offline   Reply With Quote

Old   October 29, 2010, 14:48
Default
  #4
Senior Member
 
Join Date: Feb 2010
Posts: 148
Rep Power: 17
Jade M is on a distinguished road
Thanks f-w! This link is very helpful! I'm typing the information below in case the book disappears.

In homogeneous turbulence, the fluctuating velocity field u(x,t) is statistically homogeneous. It is consistent with this definition for the mean velocity gradients d(Ui)dxj to be non-zero but uniform. A good approximation to homogeneous turbulence can be achieved in wind-tunnel experiments and homogeneous turbulence is the simplest class of flows to study using DNS.

A statistically homoegeous field U(x,t) is, by definition, statistically invariant under translations (i.e. shifts in the origin of the coordinate system). If the field is also statistically invariant under rotations and reflections of the coordinate system, then it is (statistically) isotropic.

Reference: Turbulent Flows by S. B. Pope
lvcheng, kcavatar, Anunay and 1 others like this.
Jade M is offline   Reply With Quote

Old   October 31, 2010, 00:34
Post
  #5
New Member
 
Join Date: Oct 2010
Posts: 7
Rep Power: 16
simulationman is on a distinguished road
An isotropic turbulent flow as other members have already replied, is basically a turbulent flow where the time averaged turbulent quantities ( like u r.m.s.) have the same value at each and every location.

A homogeneous flow on the other hand is one where the turbulent quantities at any given location are the same in all the directions. (ex. u r.m.s = v r.m.s.)

example a concrete wall may be isotropic if the concentration of steel and cement is the same at all locations in the wall. But it is not homogeneous because at any point, there may be steel in one direction and cement in the other direction.

Of course it is actually impossible to get either homogeneous or isotropic turbulence in a wind tunnel. But you can get close to it and ppl want to get close to it cause theoretically a homogeneous isotropic turbulence is very attractive.

And ya it is much more impossible to get actual 100% isortopic turbulence cause turbulent flows are by definition dissipative. So the turbulent quantities ( like u r.m.s.) will decay into heat energy with time. Unless you the right amount of energy at the right time it will not be isotropic.
AntonioMezzacapo likes this.
simulationman is offline   Reply With Quote

Old   January 2, 2013, 00:11
Default Mistake maybe?!
  #6
New Member
 
Join Date: Jan 2013
Posts: 1
Rep Power: 0
MaRaz is on a distinguished road
simulationman, Is definition of homogeneous and isotropic in your answer switched maybe?
MaRaz is offline   Reply With Quote

Old   January 2, 2013, 12:10
Default
  #7
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,849
Rep Power: 73
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
just to make an example, often the turbulence in channel flow is simulated, the test is composed by two parallel plates that are replicated by periodic boundary conditions. The flow is substained by a forcing pressure gradient.
This flow is simultaneously homogeneous along the two directions of periodicity and inhomogeneous in the direction normal to walls
FMDenaro is offline   Reply With Quote

Old   November 8, 2015, 00:44
Default Update?
  #8
New Member
 
Nick
Join Date: Oct 2013
Posts: 2
Rep Power: 0
ndestrad is on a distinguished road
Homogeneous turbulence: invariance in translation
Isotropic turbulence: invariance in rotation
EddySouth likes this.
ndestrad is offline   Reply With Quote

Old   January 23, 2021, 07:15
Default
  #9
Senior Member
 
Join Date: Jan 2018
Posts: 121
Rep Power: 8
Moreza7 is on a distinguished road
Quote:
Originally Posted by Jade M View Post
Thanks f-w! This link is very helpful! I'm typing the information below in case the book disappears.

In homogeneous turbulence, the fluctuating velocity field u(x,t) is statistically homogeneous. It is consistent with this definition for the mean velocity gradients d(Ui)dxj to be non-zero but uniform. A good approximation to homogeneous turbulence can be achieved in wind-tunnel experiments and homogeneous turbulence is the simplest class of flows to study using DNS.

A statistically homoegeous field U(x,t) is, by definition, statistically invariant under translations (i.e. shifts in the origin of the coordinate system). If the field is also statistically invariant under rotations and reflections of the coordinate system, then it is (statistically) isotropic.

Reference: Turbulent Flows by S. B. Pope
How can it be possible that for homogeneous turbulence where by definition:

\langle U(x,t)\rangle = \langle U(x+r,t)\rangle

then, the gradient

\frac{\partial{\langle U_i\rangle}}{\partial{x_j}}

be non-zero?!! I mean it MUST be zero!

Quote:
Originally Posted by ganesh View Post
Dear Dut_thinker,
Isotropic turbulence demands that there is no mean shear, rotation or buoyancy effects in the flow as this can lead to anisotropy. Homogeneous turbulence is indicative of the fact that there are no mean flow gradients. In a more simpler sense, homogeneity deals with invariance in translation, isotropy deals with invariance in rotation. Take a look at MIT OCW notes on turbulence if you wish for more information.

Regards,

Ganesh
For isotropic turbulence, we say that the statistical properties of the turbulence are invariant under rotations which means for example at a specific point in the domain we have:
\langle\bar{u^{'2}}\rangle = \langle\bar{v^{'2}}\rangle = \langle\bar{w^{'2}}\rangle
I think this issue has nothing to do with mean shear! Then why mean shear is zero?!
Moreza7 is offline   Reply With Quote

Old   January 23, 2021, 08:05
Default
  #10
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,849
Rep Power: 73
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
Quote:
Originally Posted by Moreza7 View Post
How can it be possible that for homogeneous turbulence where by definition:

\langle U(x,t)\rangle = \langle U(x+r,t)\rangle

then, the gradient

\frac{\partial{\langle U_i\rangle}}{\partial{x_j}}

be non-zero?!! I mean it MUST be zero!


For isotropic turbulence, we say that the statistical properties of the turbulence are invariant under rotations which means for example at a specific point in the domain we have:
\langle\bar{u^{'2}}\rangle = \langle\bar{v^{'2}}\rangle = \langle\bar{w^{'2}}\rangle
I think this issue has nothing to do with mean shear! Then why mean shear is zero?!



Plane channel flow is an example of flow homogeneous in the streamwise direction while being non-homogeneous in normal direction. It has dU/dy different from zero.
Moreza7 likes this.
FMDenaro is offline   Reply With Quote

Old   January 23, 2021, 08:56
Default
  #11
Senior Member
 
Join Date: Jan 2018
Posts: 121
Rep Power: 8
Moreza7 is on a distinguished road
Quote:
Originally Posted by FMDenaro View Post
Plane channel flow is an example of flow homogeneous in the streamwise direction while being non-homogeneous in normal direction. It has dU/dy different from zero.
Thanks for your reply.
Plane channel flow is a partially homogeneous flow (in x and z directions). I think the author is talking about a totally homogeneous flow (in every direction).
Also, if the flow is homogeneous in one direction, it does not mean that velocity must have a constant gradient in other non-homogeneous directions.
Moreza7 is offline   Reply With Quote

Old   January 23, 2021, 12:11
Default
  #12
Senior Member
 
Join Date: Jan 2018
Posts: 121
Rep Power: 8
Moreza7 is on a distinguished road
I think these statements are the best definitions of isotropic and homogeneous turbulent flow:

A turbulent flow is said to be isotropic if:
  • rotation and buoyancy are not important and can be neglected,
  • there is no mean flow.
Rotation and buoyancy forces tend to suppress vertical motions and create an anisotropy between the vertical and the horizontal directions. The presence of a mean flow with a particular orientation can also introduce anisotropies in the turbulent velocity and pressure fields.

A turbulent flow is said to be homogeneous if:
  • there are no spatial gradients in any averaged quantity.
This is equivalent to assume that the statistics of the turbulent flow are not a function of space.

[MIT OCW]
Moreza7 is offline   Reply With Quote

Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
axisymmetric homogeneous isotropic turbulence RAJANI Main CFD Forum 1 April 24, 2006 07:44
the homogeneous isotrotic compressible turbulence. loong Main CFD Forum 0 March 30, 2006 01:18
Help needed on homogeneous isotropic turbulence an Guoping Xia Main CFD Forum 0 March 12, 2006 22:54
ISOTROPIC HOMOGENEOUS TURBULENCE Valdemir Main CFD Forum 2 September 2, 2003 00:04
isotropic homogeneous turbulence tingguang Main CFD Forum 0 August 1, 2002 18:08


All times are GMT -4. The time now is 23:53.