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How to calculate the coefficient for the turbulent viscosity |
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April 2, 2021, 16:10 |
How to calculate the coefficient for the turbulent viscosity
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#1 |
New Member
Turbulence
Join Date: Apr 2021
Posts: 4
Rep Power: 5 |
Hello guys,
I am new to turbulence modeling and I have been stuck on this problem for weeks. Please help me! So I am trying to derive the k-equation in the log layer then calculate the coefficient C for the eddy viscosity vt in the form of vt=C⋅k^1/2⋅lmix. I have read the Wilcox textbook a hundred times and tons of other papers but I still have no clue how to solve for this coefficient. Does anyone know how the k-equation in the log layer looks like and how you solve for the coefficient for the eddy viscosity? Best, |
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April 3, 2021, 09:12 |
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#2 |
Senior Member
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I haven't understood what are you looking for exactly, but two of the most relevant sources on wall functions (and log layer by consequence) are the following two:
https://citeseerx.ist.psu.edu/viewdo...=rep1&type=pdf http://www.tfd.chalmers.se/~lada/pos..._report_WF.pdf Have you already looked at them for an answer? |
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April 3, 2021, 16:14 |
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#3 | |
New Member
Turbulence
Join Date: Apr 2021
Posts: 4
Rep Power: 5 |
Quote:
1:I am trying to derive the k-equation in the log-law region of a wall-bounded flow. So I used log layer assumptions. I assumed steady and fully turbulent, neglected both initial and molecular stresses, I think these are appropriate assumptions. However, I am not sure whether the turbulence kinetic energy k should be assumed to be a constant? In other two-equation models in log layer, k=ut^2/β^1/2=constant. 2: By dimensional analysis, the eddy viscosity originally has the form of Vt=Ck^1/2lmix, but in all references, they just use the constant C=1, so I am trying to figure out why C=1 or the expression for constant C. I hope that clears my questions. Thank. |
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