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Query regarding dissipation term of TKE equation |
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June 5, 2019, 09:34 |
Query regarding dissipation term of TKE equation
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#1 |
New Member
VL Srinivas
Join Date: Jan 2017
Posts: 4
Rep Power: 9 |
In TKE equation, the dissipation term can be written as:
= -2nu*<s_ij s_ij> where, nu=mu/rho is kinematic viscosity, s_ij= 0.5*{ du_i/dx_j + du_j/dx_i }, mu=dynamic viscosity, rho=density. here, u= fluctuating velocity component, d=partial derivative operator, <>=time average Considering a problem of sub-meso scale ocean modelling, 1. Is the density, instantaneous or fluctuating or mean ? 2. After doing a time average<> on the strain rate tensors, s_ij there will be no time dimension left, if the density is instantaneous, will the <s_ij s_ij> be constant over all time steps of density ? 3. If the density is constant, will be dissipation also be constant? |
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June 5, 2019, 10:56 |
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#2 |
Senior Member
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,849
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Quote:
The general analysis you find for the turbulence has a hystorical assumption, that is the density is homogeneous. For the ocean it can be introduced the Bousinnesq approximation for the bouyancy to take into account the dependence of density on low temperature gradients (actually you could also add the salinity gradient). However, the kinematic viscosity is assumed to be constant. Have a look here for the ocean flow model https://www.researchgate.net/publica...physical_flows Note that for general non-constant density flow problem, the Favre averaging is introduced. |
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June 5, 2019, 10:58 |
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#3 |
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Lucky
Join Date: Apr 2011
Location: Orlando, FL USA
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nu also needs to be averaged. Your formula implicitly assumes nu is a constant. Use a formula that doesn't assume this and a lot of your confusion will be cleared away.
Btw, Reynolds averaging works also for unsteady flows, you can extend the <> operation beyond time-averaging and allow for time-dependent flows. Think URANS! However, the answer is.... 1. Density is the reynolds average (which can be the mean, but can also be time-dependent like in unsteady RANS). But it won't be instantaneous, otherwise the TKE equation would not be a TKE equation. |
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June 6, 2019, 04:30 |
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#4 |
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VL Srinivas
Join Date: Jan 2017
Posts: 4
Rep Power: 9 |
Thank you for the replies.
By the way, in the <s_ij s_ij> term, is the multiplication, a dot product or a normal matrix product ? |
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June 6, 2019, 04:35 |
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#5 |
Senior Member
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,849
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dissipation rate, tke budget |
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