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Old   May 30, 2017, 00:59
Default Anomaly in energy spectrum
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I am computing energy spectrum for computationally obtained turbulence data, which is statistically homogeneous in 2 directions (X & Z). The energy spectrum is calculated for a homogeneous plane, using Fourier transforms of the spatial data. \vec{V}(x,z)\rightarrow\hat{V}(k_x,k_z).
The calculated spectrum shows a 'bump' at higher wavenumbers (not the highest). It is prominent in a semilog plot (attached).
I am wondering what could have resulted in this anomalous behaviour. I assume it is associated with some error in calculating the spectrum but has nothing to do with the physics. However, I am unable to find any error in the calculation.
I would like to know if anybody in the community has encountered a similar erroneous spectrum, and what could cause such anomaly?
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Old   May 30, 2017, 01:22
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You may look whether the wavelength of your bump region coincides with the size of the mesh.
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Old   May 30, 2017, 01:49
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Hi piu58,
I should have mentioned my mesh and domain earlier.
There are 512x128 points in the XZ plane which has a physical dimension 16\pi\times4\pi. Hence the maximum wavenumber for both k_x\&k_z is 32. The computed E(k) for various combinations of k_x\&k_z are binned in nearest integer values of k=\sqrt{k_x^2+k_z^2}. As you suspected, the bump corresponds to k=31,32,33.
I understand that under-resolved data results in oscillations at highest wavenumbers.In this case, I am perplexed by the smooth spectrum beyond k=32.
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Old   May 30, 2017, 04:29
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What problem are you solving, a plane channel flow? And what about the Re_tau of your problem? what about y+ of the computed spectrum?

What I do not understand is the fact you have the spectrum extending over the Nyquist frequency... Or am I wrong in understanding your comment?

Then, the magnitude of E(k) is very high, why?
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Old   May 30, 2017, 05:22
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The problem under consideration is temporal mixing layer.
On the x-axis I have k=\sqrt{k_x^2+k_z^2}, which goes up till 32\sqrt{2}. That is why the spectrum extends beyond the Nyquist limit 32. However, I am unsure about the correctness of the same.
As of now, both k and E(k) are not scaled.
My objective of plotting the spectrum is to make sure I am resolving the scales sufficiently.
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Old   May 30, 2017, 05:42
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Quote:
Originally Posted by arunsmec View Post
The problem under consideration is temporal mixing layer.
On the x-axis I have k=\sqrt{k_x^2+k_z^2}, which goes up till 32\sqrt{2}. That is why the spectrum extends beyond the Nyquist limit 32. However, I am unsure about the correctness of the same.
As of now, both k and E(k) are not scaled.
My objective of plotting the spectrum is to make sure I am resolving the scales sufficiently.
No, I strongly suggest to do the analysis along x and z direction, separately. The spectra must be computed only up to the Nyquist frequency along each direction. Furtermore, have you performed also a statistical averaging (plane and time)? Have you waited enough time to let the flow develop?
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Old   May 30, 2017, 06:03
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Quote:
Originally Posted by FMDenaro View Post
Furtermore, have you performed also a statistical averaging (plane and time)? Have you waited enough time to let the flow develop?
The spectrum corresponds to fluctuations from a plane averaged mean, during the self-similar evolution of the mixing layer. I have not performed a time averaging. It is observed that the shape of the curve remains the same at all instants.

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I strongly suggest to do the analysis along x and z direction, separately. The spectra must be computed only up to the Nyquist frequency along each direction.
Does this mean calculating one-dimensional spectrum?

To summarise, can I attribute the "bump" to the method where I am going above the Nyquist limit?
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Old   May 30, 2017, 06:31
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Compute the 1d spectra but perform the spatial averaging along the normal direction
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Old   May 31, 2017, 01:24
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Quote:
Originally Posted by FMDenaro View Post
Compute the 1d spectra but perform the spatial averaging along the normal direction
I infer this as average along Z for k_x, and vice versa. In one of the threads in this forum, it is suggested that a Fourier transform is performed first and the coefficients are averaged. Is that the right way to do it? Or should I take average before transformation?
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Old   May 31, 2017, 04:16
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Quote:
Originally Posted by arunsmec View Post
I infer this as average along Z for k_x, and vice versa. In one of the threads in this forum, it is suggested that a Fourier transform is performed first and the coefficients are averaged. Is that the right way to do it? Or should I take average before transformation?

No, you compute first the FFT and then you perform the average of the coefficients
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Old   June 1, 2017, 04:07
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The calculated one-dimensional spectrum is attached.

A smooth curve is not obtained even after averaging FFT coefficients in the Z direction. Is it required to perform an average in time to obtain a smooth spectrum?
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Old   June 1, 2017, 04:31
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That looks quite correct ... have a look at sec.5.2 here
https://www.researchgate.net/publica...-uniform_grids

and Ref.42 in the reference
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Old   June 3, 2017, 07:18
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One dimensional spectra, E(k_x)\ \& \ E(k_z), calculated from the spatial data corresponding to center plane, are attached. Here I have binned them into integer values of k_x\& k_z.

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That looks quite correct ... have a look at sec.5.2 here
In this reference, the spectrum is calculated as
E(k)=\frac{1}{2L}\int^{+L}_{-L}\left|\hat{u}(k,y)\right|^2dy,
which seems to be an averaging in the non-homogeneous direction. If so, what difference this makes to the spectrum?
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Old   June 3, 2017, 07:36
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Your results seems physically acceptable.

You can have two choices:
1) the averaging along the non-homogeneous domain give the total energy content of the mixing layer for each wavenumber component.
2) computing and analysing spectra at several stations along y+. This is for example the standard procedure for a channel flow.

Both are correct and the choice depends on what you want to analyse. I used the averaging along y to compare the solutions with the paper of Lesieur.
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Old   June 3, 2017, 07:57
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Quote:
Originally Posted by FMDenaro View Post
Your results seems physically acceptable.
Dear FMDenaro,

Thank you for your valuable suggestions.

Can you provide some clarification regarding the 'binning' procedure?
Quote:
Originally Posted by arunsmec View Post
The calculated one-dimensional spectrum is attached.
A smooth curve is not obtained even after averaging FFT coefficients in the Z direction. Is it required to perform an average in time to obtain a smooth spectrum?
In this plot, I used values of k, scaled according to the length of the domain and therefore are rational numbers.

Quote:
Originally Posted by arunsmec View Post
One dimensional spectra, E(k_x)\ \& \ E(k_z), calculated from the spatial data corresponding to center plane, are attached.
In the latter plot, the spectrum is binned to integer values of k.
E(k)=\sum_{k'} E(k'),\ \forall k'\in [k-0.5, k+0.5)
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Old   June 3, 2017, 08:12
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The plot is versus the frequency or the integer wavenumber, the relation being k=n*2*pi/L (n=0,1,2..,Nmax). The Nyquist frequency is kmax=pi/h. This is for each direction Lx and Lz.
What do you mean exactly for "binning procedure"?
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Old   June 3, 2017, 08:27
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The length of the domain in x direction is 16\pi and has 512 points. A Fourier transform of this spatial data gives amplitudes of 256 frequencies (n=0,1...256). Corresponding wavenumbers are k=0,1/8,2/8.....,32 and they are not all integers.

In the latter plot, I have used only integer values of wavenumber on the x-axis. The energy of non-integer wavenumbers is rounded off to nearest integer k. For example, E(1) is the sum of all u(k)^2 for k=4/8,5/8,.....,10/8,11/8.
This procedure was described in a reference, but I couldn't trace it now.
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Old   June 3, 2017, 08:38
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After you perform the FFT, you have a vector of the complex Fourier coefficients for each integer n=0,1,... Thus, you can plot (in a log scale) the modulus versus these non-dimensional numbers or you simply convert the integers in the dimensional spatial frequency k = n*2*pi/L.
No "binning" in such procedure...
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