Simple vector notation help. uiuj in non index notation

meangreen · October 4, 2012, 13:39

Hey Everyone,

For my paper I have about 50 equations all in the "standard" vector notation
$\vec{u}$ , but there are 2 or 3 turbulence equations with the Reynolds stress therm in index notation that I don't know how to put in the "standard form". The term is below:

= ??? in standard form

I think $\vec{u}^2$ is not correct or at least will make the reader think I am talking about the dot product of u with u.

meangreen · October 4, 2012, 13:48

My friend just said he thinks it is

$u_iu_j=\vec{u}\vec{u}$

agd · October 4, 2012, 14:01

If you are referring to the terms in the Reynolds stress tensor, your friend is correct. The term for such a representation is dyadic.

meangreen · October 4, 2012, 14:11

I just had another friend say it is the outer product, so

$u_iu_j=\vec{u}\otimes\vec{u}$

is it basically the same thing?

$\vec{u}\vec{u}=\vec{u}\otimes\vec{u}$ ?

agd · October 4, 2012, 17:34

They are not the same thing. The outer product of two vectors is another vector. The inner product of two vectors is, of course, a scalar. The dyadic product of two vectors is a tensor of order 2 (since the vectors are each tensors of order 1). When you write the index notation (ui)(uj) without any caveats, it generally implies the dyadic product.

meangreen · October 5, 2012, 11:23

I just looked and according to wiki (i know, i know) the outer product does produce a tensor. Are you sure about your answer?

cdegroot · October 7, 2012, 12:05

Quote:

Originally Posted by meangreen

I just had another friend say it is the outer product, so

$u_iu_j=\vec{u}\otimes\vec{u}$

is it basically the same thing?

$\vec{u}\vec{u}=\vec{u}\otimes\vec{u}$ ?

First equation is correct. Second one should be $\vec{u}\vec{u}^T=\vec{u}\otimes\vec{u}$ assuming column vectors.

agd · October 7, 2012, 12:07

Sorry - I saw the symbol and my brain interpreted it as the cross product. Yes, the outer product results in the same thing as the dyadic product. It is not the same thing as the cross product, which produces a tensor of the same order as the original entries.

October 4, 2012, 13:39	Simple vector notation help. uiuj in non index notation	#1
meangreen Member Casey Join Date: Jun 2009 Posts: 98 Rep Power: 17	Hey Everyone, For my paper I have about 50 equations all in the "standard" vector notation $\vec{u}$ , but there are 2 or 3 turbulence equations with the Reynolds stress therm in index notation that I don't know how to put in the "standard form". The term is below: = ??? in standard form I think $\vec{u}^2$ is not correct or at least will make the reader think I am talking about the dot product of u with u.

October 4, 2012, 14:01		#3
agd Senior Member Join Date: Jul 2009 Posts: 358 Rep Power: 19	If you are referring to the terms in the Reynolds stress tensor, your friend is correct. The term for such a representation is dyadic. meangreen likes this.

October 7, 2012, 12:07		#8
agd Senior Member Join Date: Jul 2009 Posts: 358 Rep Power: 19	Sorry - I saw the symbol and my brain interpreted it as the cross product. Yes, the outer product results in the same thing as the dyadic product. It is not the same thing as the cross product, which produces a tensor of the same order as the original entries. meangreen likes this.

Similar Threads
Thread	Thread Starter	Forum	Replies	Last Post
gamma-ReTheta turbulence model for predicting transitional flows	FelixL	OpenFOAM Programming & Development	123	August 30, 2022 12:50
FvMatrix coefficients	shrina	OpenFOAM Running, Solving & CFD	10	October 3, 2013 15:38
Doxygen documentation	Tanay	OpenFOAM Installation	9	September 23, 2011 12:40
OpenFOAM install on Ubuntu Natty 11.04	bkubicek	OpenFOAM	13	May 26, 2011 06:48
Notation Standards and Uniformity	yNot	CFD-Wiki	0	April 5, 2008 16:00

October 4, 2012, 13:48		#2
meangreen Member Casey Join Date: Jun 2009 Posts: 98 Rep Power: 17	My friend just said he thinks it is $u_iu_j=\vec{u}\vec{u}$

October 4, 2012, 14:11		#4
meangreen Member Casey Join Date: Jun 2009 Posts: 98 Rep Power: 17	I just had another friend say it is the outer product, so $u_iu_j=\vec{u}\otimes\vec{u}$ is it basically the same thing? $\vec{u}\vec{u}=\vec{u}\otimes\vec{u}$ ?

October 4, 2012, 17:34		#5
agd Senior Member Join Date: Jul 2009 Posts: 358 Rep Power: 19	They are not the same thing. The outer product of two vectors is another vector. The inner product of two vectors is, of course, a scalar. The dyadic product of two vectors is a tensor of order 2 (since the vectors are each tensors of order 1). When you write the index notation (ui)(uj) without any caveats, it generally implies the dyadic product.

October 5, 2012, 11:23		#6
meangreen Member Casey Join Date: Jun 2009 Posts: 98 Rep Power: 17	I just looked and according to wiki (i know, i know) the outer product does produce a tensor. Are you sure about your answer?