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Integral representation of a generic function |
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July 5, 2012, 04:23 |
Integral representation of a generic function
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#1 |
New Member
Ali
Join Date: Apr 2010
Location: Greenville, South Carolina, USA
Posts: 11
Rep Power: 16 |
Hey guys,
I've just started reading SPH book by Liu & Liu. In second chapter, I faced with an expression which says the integral representation of a generic function is: f(x)=int[f(x')*DeltaDirac(x-x')*dx'] I cannot understand the concept behind this formulation. Could anyone someone please help me to get through it? you know, this is somehow none-sense for me, when x'-->x then we are going to have something like this: {f(x)=int[f(x')*1*dx'] where x=x'} so it means that {f(x)=int[f(x)*dx]}!!!! Please correct me if I am wrong, I do appreciate your help. |
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July 5, 2012, 05:25 |
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#2 | |
Senior Member
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,896
Rep Power: 73 |
Quote:
No, Dirac(0) goes to infinity, is its integral to be finished and =1. That defines the function f at a position x |
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sph method |
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