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how to use VOF with a free surface?

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Old   February 1, 2011, 15:09
Default how to use VOF with a free surface?
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hello;
i am working on Taylor Couette system, it's two concentric cylindres with the inner is rotating, the gap between the two cylindres is not full of fluide-benzene-, it means there are two phases air and benzene with free surface (between the two phases.
using VOF, i always find one phase (benzene) as a result in the gap, please help me.
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Old   February 2, 2011, 22:14
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Are you initializing your solution with only one phase (volume frac of benzene=1)? If not, is there a way for air to leave the system and benzene to enter?

ComputerGuy

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Originally Posted by alilouu View Post
hello;
i am working on Taylor Couette system, it's two concentric cylindres with the inner is rotating, the gap between the two cylindres is not full of fluide-benzene-, it means there are two phases air and benzene with free surface (between the two phases.
using VOF, i always find one phase (benzene) as a result in the gap, please help me.
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Old   February 3, 2011, 16:44
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thanks for intersting computerGuy, there is no velicity inlet for each phases, it means the only move is the rotation of the inner cylinder. the the volume fraction of air is 0.53
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Old   February 3, 2011, 16:56
Default vof ??
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thanks computerGuy
i initiallsed the calcul with two volume fractions; 0.53 for air, and 0.47 for benzene, but in the end , i find only one phase, there is no motion (velocity inlet) for each phases, only the inner cylinder which is rotating
like is shown in the picture;
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Old   March 22, 2011, 13:37
Default simulating Taylor Couette problem
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hi ;
is there someone hwo knows sources about simulating a free surface in the taylor couette problem........ really i found only the work of watanabe et al.
thanks a lot
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Old   November 15, 2011, 03:55
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Originally Posted by alilouu View Post
thanks for intersting computerGuy, there is no velicity inlet for each phases, it means the only move is the rotation of the inner cylinder. the the volume fraction of air is 0.53
are you taking a co current case or a counter current case....
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