[jugal44j]

I am performing analysis on "FLOW AROUND CYLINDER"

I am getting xy plot of Nu Vs Direction vector & Nu Vs curve length in fluent.
But I need these graph as Nu vs angle on cylinder (theta(/)).

How can I plot this type of graph?

say Any quantity i.e. Nu, Cp, h vs Angle {theta(/)}?

for your reference attaching here 2 figs.

I have run analysis on Re.100 and Re.200 & I want to know that how to get recirculation length and separation angle from fluent?

Please reply soon... its urgent.. Thx. in advance...

[khairy]

Hi Jugal,

if you plot any variable ( plot--> xy plot) against the curve length (the abscissa), and the line at which you plot is around the cylinder,
the abscissa is (radius x theta)

so if you write this xy plot to a file

you can simply divide the curve length (the first column in the file) by cylinder radius then multiply by 180/pi to have theta in degrees. you can perform this in Excel or write any simple code to perform this simple calculations. If you are aware with custom field function in FLUENT you may use it instead.

May be there are many other solutions. but this method works well with me.

Regards,

Khairy

[jugal44j]

its worked well within my case too...

Thx.. good bye

[bestniaz]

Originally Posted by khairy

Hi Jugal,

if you plot any variable ( plot--> xy plot) against the curve length (the abscissa), and the line at which you plot is around the cylinder,
the abscissa is (radius x theta)

so if you write this xy plot to a file

you can simply divide the curve length (the first column in the file) by cylinder radius then multiply by 180/pi to have theta in degrees. you can perform this in Excel or write any simple code to perform this simple calculations. If you are aware with custom field function in FLUENT you may use it instead.

May be there are many other solutions. but this method works well with me.

Regards,

Khairy

Sir its been so long to post the question in the same thread...but I need your help..

I am also studying the flow around cylinder.
When I plot the wall shear against the cylinder curve.... the plot appear as shown in image 1...but I want to plot the wall shear against the thetha...so according to your suggestion I export the data in excel form but when I plotted the result there..the chart is very different then the CFX post plot... please help me to make this point clear...

When I tried to transfer that data to thetha...it also not work..

Please explain it
In my case study
Diameter of cylinder is 0.1m,,,so how it can be converted to angle if I want to plot it

[LuckyTran]

Originally Posted by bestniaz

Sir its been so long to post the question in the same thread...but I need your help..

I am also studying the flow around cylinder.
When I plot the wall shear against the cylinder curve.... the plot appear as shown in image 1...but I want to plot the wall shear against the thetha...so according to your suggestion I export the data in excel form but when I plotted the result there..the chart is very different then the CFX post plot... please help me to make this point clear...

When I tried to transfer that data to thetha...it also not work..

Please explain it
In my case study
Diameter of cylinder is 0.1m,,,so how it can be converted to angle if I want to plot it

The charts are the same! You need to export both x & y coordinates. Then do a coordinate transform from x,y into theta. It sounds complicated but it's just a simple algebra/trigonometry problem. And there's lots of ways to do it. via the curve length route is an ad-hoc approximate way (but doable in Fluent with custom field functions because it's only uses simple functions). Since you are already in excel you just need to do (x-xo),(y-y0) where x0,y0 is the polar origin and then use your favorite inverse trig function (asin, acos, or atan) to figure out the angle.

[bestniaz]

Originally Posted by LuckyTran

The charts are the same! You need to export both x & y coordinates. Then do a coordinate transform from x,y into theta. It sounds complicated but it's just a simple algebra/trigonometry problem. And there's lots of ways to do it. via the curve length route is an ad-hoc approximate way (but doable in Fluent with custom field functions because it's only uses simple functions). Since you are already in excel you just need to do (x-xo),(y-y0) where x0,y0 is the polar origin and then use your favorite inverse trig function (asin, acos, or atan) to figure out the angle.

Thank you thank you and thank you so much,,,
It was so simple thing, but I was stuck in that...

Really love this forum ...specially the senior of this forum are really helpful.