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Inconsistency in Fluent results with calculation |
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February 3, 2020, 18:03 |
Inconsistency in Fluent results with calculation
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#1 |
Member
Abhinand
Join Date: Jun 2016
Posts: 75
Rep Power: 10 |
Hi all,
I do not know why an inconsistency in results from fluent and analytical calculation For eg: Skin friction coeff : From fluent (as field variable) By calculation : tau = mu*(dx-velocity-dy) I computed both and I found to be consistent But when I check the heat flux calculation Total surface heat flux (From fluent Field variable) By hand calculation: Kair*(gradient-dt-dy) is vastly different from the value given by fluent From fluent manual: For an isothermal wall BC, the heat flux is calculated by Q = Hf*(Tw-Tf) Hf = local fluid heat transfer coefficient Tf = local fluid temperature The Hf given by fluent is given by Q/(Tw - Tf) Tf specified in reference tables But how does it calculate the Q?? I want to know how does fluent calculate the total surface heat flux. |
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February 4, 2020, 04:10 |
From the first principle
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#2 |
Senior Member
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Fluent solve energy equation and as a solution it has temperature field available. Using the gradient of this and thermal properties of the material, q is just diffusion heat flux. Do note that this also includes diffusion due to the turbulence, provided the flow is turbulent. And diffusion due to the turbulence could be significant, even close to the wall.
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Regards, Vinerm PM to be used if and only if you do not want something to be shared publicly. PM is considered to be of the least priority. |
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February 4, 2020, 16:43 |
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#3 |
Member
Abhinand
Join Date: Jun 2016
Posts: 75
Rep Power: 10 |
Thank you for your answer vinerm,
Can you please elaborate on how turbulent diffusivity (mu_t) comes into picture while calculating heat flux. Is my understanding correct? Correct me if Im wrong Q = -K(gradient dt-dy) gradient is calculated by fluent after solving the temperature field K = Klam + kturb Kturb = cp*mu_t/Pr_t I have an extremely turbulent boundary layer and my Kturb is like 200 times smaller than K. Please advise on how the computation is done by fluent Thanks -Abhinand |
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February 5, 2020, 04:43 |
You are correct
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#4 |
Senior Member
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Yes, that's how Fluent computes the flux for every field. BL are so called because within them effects of turbulence more or less vanish and viscous forces take over. However, Fluent uses effective diffusivity since mesh close to wall may or may not have been resolved. Furthermore, the relation you mentioned is based on first-principle. Fluent does it slightly differently. Look at Theory Guide Section on Near-Wall Treatment for Energy within Turbulence chapter.
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Regards, Vinerm PM to be used if and only if you do not want something to be shared publicly. PM is considered to be of the least priority. |
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Tags |
gradient calculation, heat transfer, heat transfer coefficient, heatflux |
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