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Modeling Turbulent Flow - Not Getting Correct Velocity Profile |
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March 11, 2018, 22:23 |
Modeling Turbulent Flow - Not Getting Correct Velocity Profile
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#1 |
New Member
H. M.
Join Date: Feb 2018
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I am modeling turbulent flow in a simple straight pipe. I have confirmed that this flow is turbulent with a Re of 11,000, however the velocity profile I get looks laminar.
I have tried all k - epsilon models, and the SST model. Still nothing. What could be wrong? I have been trying to figure this out for days. |
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March 12, 2018, 00:24 |
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#2 | |
Senior Member
Alexander
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Best regards |
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March 12, 2018, 09:47 |
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#3 |
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H. M.
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March 12, 2018, 12:01 |
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#4 |
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Cees Haringa
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Dimensionless wall distance, relevant for boundary layer development. it shouldn't matter too much when working with the k-e model though, assuming you use wall functions.
Can you show the velocity profile? |
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March 12, 2018, 12:18 |
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#5 |
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Lucky
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Are you simulating the entrance problem? I.e. How long is your pipe?
What are your inlet BC's? Did you give the inlet a reasonable turbulence intensity and length scale? |
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March 12, 2018, 12:38 |
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#6 | |
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H. M.
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Quote:
Here is the velocity profile. For calculated Re of about 11,000! https://ibb.co/ngPBxn |
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March 12, 2018, 12:40 |
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#7 | |
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H. M.
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I have not introduced any inlet pressure, just an inlet velocity of 1.143 m/s which is 45 in/s. The working fluid here is liquid water. I used the setting which asks for intensity (which i calculated to be 5%) and hydraulic length, so my pipe inner diameter of 0.37in. |
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March 12, 2018, 13:19 |
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#8 |
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Cees Haringa
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It already looks more flat than a true laminar profile. But judging from the image, you have a very crude mesh (6-7 cells in the diameter?), first, refine the mesh. I am quite certain that with something like 20 cells in the diameter the solution would already be quite different. Since gradients are to be expected near the wall, a finer mesh near the wall would be beneficial (this does link to the y+, although when using wall functions your y+ does not have to be nearly as low as without). Also, as LuckyTran mentions, it matters where you measure - keep into account your starting profile is uniform, and will need some time (= distance) to develop to turbulent.
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March 12, 2018, 13:37 |
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#9 | |
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H. M.
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Quote:
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March 12, 2018, 13:39 |
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#10 | |
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H. M.
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March 12, 2018, 13:55 |
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#11 |
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Alex
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Too little information.
Show the mesh you used, the solver settings, convergence criteria, where did you extract that line plot, use more points for the plot, use coordinate instead of chart count on the x-axis... And sorry to bring this up: did you make sure that your imperial units were used correctly throughout the whole simulation process? |
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March 12, 2018, 14:25 |
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#12 | |
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H. M.
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Quote:
https://ibb.co/g9cWDS https://ibb.co/kOZHnn https://ibb.co/hs4TtS https://ibb.co/dOknL7 https://ibb.co/erqRDS |
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March 12, 2018, 16:01 |
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#13 |
Super Moderator
Alex
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Any particular reason why you are using mesh interfaces for this case? If not, drop them.
My psychic abilities tell me that the line you used for post-processing might only evaluate results in the center domain of your mesh. This could be visible if we had a coordinate instead of a chart count on the x-axis |
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March 12, 2018, 16:02 |
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#14 |
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H. M.
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March 12, 2018, 16:18 |
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#15 |
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Alex
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This should help you get a nice looking mesh without interfaces: Pipe bend meshing using MultiZone
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March 12, 2018, 19:00 |
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#16 | |
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H. M.
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I also forgot to add, I added in streamlines and started an animation and the flow was still not turbulent. :/ Thank you guys for helping me out, much appreciated! |
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March 12, 2018, 19:45 |
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#17 | |
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Alex
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It seems like your mesh consists of at least two domains. One in the center of the pipe and one around the wall. If your plot only contains results from the center of the pipe, it could kind of make sense. But again, several domains with interfaces are not beneficial here.
We could confirm this theory if you put a coordinate instead of a chart count on the x-axis which we could compare to the dimensions of the pipe. Quote:
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March 12, 2018, 21:48 |
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#18 | |
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H. M.
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Quote:
Yes, I am assuming steady state. |
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