CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > Software User Forums > ANSYS > FLUENT

Von-Karman vortex street - Reynolds number range

Register Blogs Community New Posts Updated Threads Search

Like Tree5Likes
  • 1 Post By FMDenaro
  • 1 Post By FMDenaro
  • 1 Post By spl
  • 1 Post By truffaldino
  • 1 Post By FMDenaro

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   May 21, 2015, 15:43
Default Von-Karman vortex street - Reynolds number range
  #1
New Member
 
nima
Join Date: Sep 2011
Posts: 26
Rep Power: 15
nima_nzm is on a distinguished road
Dear Friends,

I am trying to model flow around a 2D cylinder in Fluent 6.3 and capture vortices shedding. I did the same project in Reynolds number ranging 100-4500 with reasonable results. But now I am doing a project with Air as fluid and cylinder diameter of 0.05 m. other specifications are:

V = 10 m/s
Solver = unsteady 2nd order
Viscous = k-e standars
solution=second order upwind
time step=0.005
time = up to 100 s (even more sometimes)

My reynolds number is around 10000. I am not sure if I should expect von karman vortex street in this reynolds number. my result is only a fully developed and symmetric flow behind the cylinder without any vortex.
attached picture is contour of vorticity magnitude

Help me if there is a reynold range for vortex shedding in cylinder case.

Thanks
Attached Images
File Type: jpg v.jpg (34.8 KB, 85 views)
nima_nzm is offline   Reply With Quote

Old   May 21, 2015, 16:05
Default
  #2
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,882
Rep Power: 73
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
Quote:
Originally Posted by nima_nzm View Post
Dear Friends,

I am trying to model flow around a 2D cylinder in Fluent 6.3 and capture vortices shedding. I did the same project in Reynolds number ranging 100-4500 with reasonable results. But now I am doing a project with Air as fluid and cylinder diameter of 0.05 m. other specifications are:

V = 10 m/s
Solver = unsteady 2nd order
Viscous = k-e standars
solution=second order upwind
time step=0.005
time = up to 100 s (even more sometimes)

My reynolds number is around 10000. I am not sure if I should expect von karman vortex street in this reynolds number. my result is only a fully developed and symmetric flow behind the cylinder without any vortex.
attached picture is contour of vorticity magnitude

Help me if there is a reynold range for vortex shedding in cylinder case.

Thanks

Well, a couple of comments from the picture ... you are modelling the turbulence via (U)RANS approach but the solution you computed is statistically steady. That means you would accept that turbulence fluctuations at high Re number do not appear in the stationary averaged field. However, URANS allows potentially for some unsteady energy component to be described if the frequency is low.

Try to eliminate any turbulence modelling, using second order upwind you can perform an ILES simulation that should allow you to see some unsteady shedding.
nima_nzm likes this.
FMDenaro is offline   Reply With Quote

Old   May 21, 2015, 17:50
Default
  #3
New Member
 
nima
Join Date: Sep 2011
Posts: 26
Rep Power: 15
nima_nzm is on a distinguished road
Quote:
Originally Posted by FMDenaro View Post
Well, a couple of comments from the picture ... you are modelling the turbulence via (U)RANS approach but the solution you computed is statistically steady. That means you would accept that turbulence fluctuations at high Re number do not appear in the stationary averaged field. However, URANS allows potentially for some unsteady energy component to be described if the frequency is low.

Try to eliminate any turbulence modelling, using second order upwind you can perform an ILES simulation that should allow you to see some unsteady shedding.
FMDenaro,

I did it again with choosing Laminar model for viscous model. Vortices are generated. but is it reasonable to use laminar model for a flow with RE=10000. Is that your mean to use laminar model instead of URANS?
nima_nzm is offline   Reply With Quote

Old   May 21, 2015, 18:45
Default
  #4
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,882
Rep Power: 73
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
if the grid is sufficiently fine (cell Reynolds O(1)) you can consider that the DNS apporoach that does not require any turbulence model.
nima_nzm likes this.
FMDenaro is offline   Reply With Quote

Old   May 22, 2015, 10:24
Default
  #5
spl
Member
 
spl
Join Date: Nov 2014
Posts: 33
Rep Power: 12
spl is on a distinguished road
Have a look at this link -

http://www.thermopedia.com/content/1...id=104&sn=1410

This should give you some information about what you should expect to see at different Reynolds numbers.
nima_nzm likes this.
spl is offline   Reply With Quote

Old   May 22, 2015, 10:40
Default
  #6
Senior Member
 
truffaldino's Avatar
 
Join Date: Jan 2011
Posts: 249
Blog Entries: 5
Rep Power: 17
truffaldino is on a distinguished road
Quote:
Originally Posted by FMDenaro View Post
if the grid is sufficiently fine (cell Reynolds O(1)) you can consider that the DNS apporoach that does not require any turbulence model.

But for that one should to do 3d simulations instead 2d. Do you think it is realistic to run on PC at Re=10^4 ?
nima_nzm likes this.
truffaldino is offline   Reply With Quote

Old   May 22, 2015, 10:52
Default
  #7
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,882
Rep Power: 73
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
Quote:
Originally Posted by truffaldino View Post
But for that one should to do 3d simulations instead 2d. Do you think it is realistic to run on PC at Re=10^4 ?

Of course, DNS is always 3D apart some specific geophysical 2D DNS simulations.

As the feasibility of a DNS on a cylinder at Re=10^4 is concerned, I based my assumption on the fact that DNS of plane channel flow is now realized at Re_tau more than 10^3, that means the Re based on the channel height is about 20 times greater. But that can be performed on specific HPC platform.
nima_nzm likes this.
FMDenaro is offline   Reply With Quote

Old   May 23, 2015, 15:49
Default
  #8
New Member
 
nima
Join Date: Sep 2011
Posts: 26
Rep Power: 15
nima_nzm is on a distinguished road
Quote:
Originally Posted by spl View Post
Have a look at this link -

http://www.thermopedia.com/content/1...id=104&sn=1410

This should give you some information about what you should expect to see at different Reynolds numbers.

the link does not work...
nima_nzm is offline   Reply With Quote

Old   May 24, 2015, 07:40
Default
  #9
spl
Member
 
spl
Join Date: Nov 2014
Posts: 33
Rep Power: 12
spl is on a distinguished road
Quote:
the link does not work...
Have you managed to access the link yet? I had trouble with it last night but it seems to be fine this morning.
spl is offline   Reply With Quote

Old   May 26, 2015, 12:17
Default
  #10
New Member
 
nima
Join Date: Sep 2011
Posts: 26
Rep Power: 15
nima_nzm is on a distinguished road
Quote:
Originally Posted by spl View Post
Have you managed to access the link yet? I had trouble with it last night but it seems to be fine this morning.
Yes it works now. thank you
nima_nzm is offline   Reply With Quote

Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
decomposePar pointfield flying OpenFOAM Running, Solving & CFD 28 December 30, 2013 16:05
CFX Error - Reynolds number out of range saisanthoshm88 CFX 3 May 11, 2012 08:04
Karman Vortex street Apocolapse STAR-CCM+ 2 December 12, 2011 11:53
[Commercial meshers] Trimmed cell and embedded refinement mesh conversion issues michele OpenFOAM Meshing & Mesh Conversion 2 July 15, 2005 05:15
Kármán vortex street (article)? Vortexstr Main CFD Forum 0 February 9, 2000 07:47


All times are GMT -4. The time now is 17:11.