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Discretization of transient terms in steady state |
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November 4, 2021, 12:07 |
Discretization of transient terms in steady state
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#1 |
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anonymous
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Hi,
I know that CFX uses a pseudo-transient approach to reach a steady state solution. However, I could not find any information in the solver-theory manual or in this forum if CFX uses a 1st or 2nd order backward euler scheme to discretize the transient terms. Maybe I'm missing something but does anybody know where I could find this information? Thanks and have a good day! |
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November 4, 2021, 13:29 |
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#2 |
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Your question confused two things:
Pseudo transient discretization vs True transient discretization transient discretization order methods have no relevance in the pseudo-transient approach since the solution should be independent of how it got there. I think you are asking for something else. Let us see what that really is.
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November 4, 2021, 14:48 |
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#3 |
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anonymous
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Thanks for the quick response!
Please correct me if I'm wrong in the following. The set of governing equations is discretized in time even for steady calculations in CFX with a "false" time step. So time proceeds until a steady state solution is obtained. In order to solve the transient term in the discretized equations I need a scheme or method to do it. In the theory guide two are presented namely 1st and 2nd order backward euler. And that's where my questions aims at. I want to know which scheme CFX uses for the steady state case. The Fluent theory guide explains everything pretty clearly, but I want to know how it is done in CFX. |
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November 4, 2021, 15:17 |
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#4 |
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It may look for some like 1st order discretization, but it is not.
If you thought from the Fluent theory that is a transient scheme, then the answer you want is: "the same as shown in the Fluent theory" Nothing different.
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November 4, 2021, 15:34 |
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#5 |
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anonymous
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So what is it then? Is there any paper/book/manual or something which describes properly what CFX does?
Last edited by LuckyGuy; November 4, 2021 at 17:03. |
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November 4, 2021, 17:30 |
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#6 |
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Exactly as described in the Fluent theory page
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November 5, 2021, 04:11 |
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#7 |
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anonymous
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I missed things up yesterday and got confused, but I think now it's clear to me.
So, CFX uses a implicit pseudo-transient under relaxation (see Fluent Theory Chap. 24.6 "Pseudo Transient Under-Relaxation", Eq. 24.99) to march to the steady state solution. Is there a general formula to describe this and how are the coefficients calculated in this equation? |
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November 5, 2021, 04:37 |
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#8 |
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Glenn Horrocks
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The coefficients are the linearisation of the non-linear terms in the Navier Stokes equations. They are updated each coefficient loop. This is also in the Fluent Theory manual, section 24.2 (especially 24.2.1).
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November 5, 2021, 05:13 |
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#9 |
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anonymous
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Now everything is clear. Didn't know CFX and Fluent use the same method, that's what got me confused, I guess. Thanks for helping me!
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November 5, 2021, 06:12 |
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#10 |
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Glenn Horrocks
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A key reason Fluent and CFX came together under the ANSYS company was so they could share key bits of their respective technologies. Fluent did not originally have the coupled solver.
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steady state |
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