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  • Navier-Stokes equations
    </td><td width="5%">(6)</td></tr> </td><td width="5%">(6)</td></tr></table>
    29 KB (4,606 words) - 18:17, 28 August 2012
  • Posdat.f
    LQ(6,IC): the x direction neighbor cell; LQ(6,IC): the z direction neighbor cell;
    3 KB (540 words) - 12:13, 3 September 2011
  • Reynolds stress model (RSM)
    ...theorie nichthomogener turbulenz.|rest=Zeitschrift für Physik A, Vol. 129(6), pp. 547-572}}
    8 KB (1,203 words) - 01:47, 18 April 2017
  • Near-wall treatment for k-omega models
    \omega_\text{vis} = \frac{6\nu}{\beta y^2} & \omega_\text{log} = \frac{u_\tau}{C_\mu^{1/4} \kappa y}
    4 KB (581 words) - 10:40, 31 March 2021
  • Best practice guidelines for turbomachinery CFD
    ...ion in a Transonic Turbine|rest=AIAA Journal of Propulsion and Power, vol. 6, no. 5}}
    41 KB (6,252 words) - 08:46, 4 March 2023
  • Baldwin-Lomax model
    </math></td><td width="5%">(6)</td></tr></table> F_{KLEB}(y) = \left[1 + 5.5 \left( \frac{y \, C_{KLEB}}{y_{MAX}} \right)^6
    8 KB (1,262 words) - 09:15, 3 January 2012
  • Ansys FAQ
    ...tation. Specifically section 15 ("Advice on Flow Modeling"), section 15.10.6 ("Problems with Convergence"), and any best practice guides applicable to y 6. Postprocess both the CFD and solids results in CFX-Post.
    27 KB (4,461 words) - 02:03, 18 August 2018
  • Large eddy simulation (LES)
    ...for large-eddy simulation in complex geometries|rest=Physics of Fluids, 19(6): 065110, 2007}}
    6 KB (882 words) - 21:50, 24 June 2013
  • Spalart-Allmaras model
    ...ac{ 1 + C_{w3}^6 }{ g^6 + C_{w3}^6 } \right]^{1/6}, \quad g = r + C_{w2}(r^6 - r), \quad r \equiv \frac{\tilde{\nu} }{ \tilde{S} \kappa^2 d^2 }
    4 KB (662 words) - 13:34, 23 April 2015
  • Gauss-Seidel method
    | 6.1237E-01 | 6.2500E-01
    8 KB (1,113 words) - 09:15, 3 January 2012
  • Jacobi method
    | 6.1237E-01 | 6.2500E-01
    6 KB (825 words) - 09:15, 3 January 2012
  • Realisable k-epsilon model
    <math> A_0 = 4.04, \; \; A_s = \sqrt{6} \cos \phi </math> <br> <math> \phi = \frac{1}{3} \cos^{-1} (\sqrt{6} W), \; \; W = \frac{S_{ij} S_{jk} S_{ki}}{{\tilde{S}} ^3}, \; \; \tilde
    2 KB (380 words) - 19:57, 16 December 2014
  • Approximation Schemes for convective term - structured grids - Summary of Discretizations Schemes and examples
    </td><td width="5%">(6)</td></tr></table> </td><td width="5%">(6)</td></tr></table>
    9 KB (1,327 words) - 05:56, 21 April 2012
  • Approximation Schemes for convective term - structured grids - Common
    </td><td width="5%">(6)</td></tr></table> ... | rest=International Journal for Numerical Methods in Fluids, Vol. 8, No. 6, pp. 617-641}}
    28 KB (4,096 words) - 13:11, 24 October 2016
  • LES filters
    G(x) = \left( \frac{6}{\pi \Delta^2} \right)^{1/2} e^{ \frac{-6 x^2}{\Delta^2}}
    2 KB (283 words) - 09:15, 3 January 2012
  • Sand box Approximation Schemes
    \end{array}} \right . \quad \quad ( 6)</math> ... Meth. Fluids |volume=8 |page=617–641 |doi=10.1002/fld.1650080602 |issue=6|bibcode = 1988IJNMF...8..617G }}
    26 KB (3,687 words) - 20:19, 7 November 2011
  • V2-f models
    ...} = 1</math>, <math>C_1 = 1.4</math>, <math>C_2 = 0.45</math>, <math>C_T = 6</math>, <math>C_L = 0.25</math> and <math>C_{\eta} = 85</math>. <math>T = \max \left[ \min \left( \frac{k}{\varepsilon},\, \frac{0.6}{\sqrt{6} C_{\mu} |S|\zeta} \right), C_T \left( \frac{\nu}{\varepsilon} \right)^{1/
    6 KB (917 words) - 05:45, 7 February 2014
  • Ahmed body
    [6] M. Minguez, R. Pasquetti, E. Serre, High-order large-eddy simulation of fl
    4 KB (577 words) - 05:46, 6 October 2015
  • CHAM FAQ
    :''ACP=1.6582; BCP=-8.479E-4; CCP=4.4541E-7; DCP=-2992.6'' :''(stored of SODV is EXP(-6.4406-0.3958*LOGE(TDEK)+556.835/TDEK)!ZSLSTR)''
    37 KB (5,717 words) - 12:46, 9 December 2019
  • Turbulence intensity
    ...oth- and rough-wall pipe flow. Code for an example in [5] can be found in [6]. A high Reynolds number transition in the scaling has been characterized i {{reference-paper|author=[6] Basse, N.T.|year=2019|title=Python code to calculate turbulence intensity
    5 KB (661 words) - 16:24, 23 July 2022
  • Introduction to turbulence/Reynolds averaged equations
    </td><td width="5%">(6)</td></tr></table> <font color="orange" size="3">Figure 3.6 not uploaded yet</font>
    45 KB (7,578 words) - 08:35, 21 August 2013
  • Flow around a circular cylinder
    [6] Dennis, S. C. R. and Chang, G.-Z., 1970, Numerical solutions for steady fl ... turbulence models // J. Engineering Physics and Thermophysics. Vol.78. No.6. pp. 1199-2013.
    6 KB (884 words) - 11:31, 8 April 2017
  • Introduction to turbulence/Turbulence kinetic energy
    </td><td width="5%">(6)</td></tr></table> ...xtra assumptions about the last term. It is only the last term in equation 6 that can be identified as the true rate of dissipation of turbulence kineti
    47 KB (7,664 words) - 12:47, 13 December 2013
  • Tdyn
    ...te calculus-finite element formulation|rest=Int. Jnl. Num. Meth. Fluids 54(6-8): 609-637}}
    3 KB (388 words) - 09:14, 3 January 2012
  • Stratford's separation criterion
    C'_p \cdot \sqrt{x' \frac{dC'_p}{dx}} = k \cdot \left( \frac{Re}{10^6} \right) ^ {0.1}
    3 KB (543 words) - 11:10, 11 December 2013
  • Introduction to turbulence/Homogeneous turbulence
    Figure 6.1 shows an attempt to correlate some of the grid turbulence data using the ...el too comfortable about this, let's look at another curve shown in figure 6.2. This one is also due to Sreenivasan, but a compiled a decade later and b
    10 KB (1,751 words) - 13:03, 21 March 2012
  • Introduction to turbulence/Free turbulent shear flows
    ...shear flows have in common with the homogeneous flows discussed in Chapter 6 is that their scales continue to grow as long as the flow remains turbulent </td><td width="5%">(6)</td></tr></table>
    67 KB (11,204 words) - 13:42, 19 April 2016
  • Main Cavity.f90 - Main modul
    x_exct(6)=0.1563 ; v_exct(6)= 0.37095 y_exct(6)=0.1719 ; u_exct(6)=-0.38289
    7 KB (885 words) - 14:54, 19 May 2016
  • Introduction to turbulence/Wall bounded turbulent flows
    </td><td width="5%">(6)</td></tr></table>
    41 KB (7,002 words) - 13:02, 21 March 2012
  • PFV4 diffusion matrix
    % functions with 3, 4, or 6 degrees-of-freedom and defined on a nndofs = eu.nndofs; % nndofs = number of dofs per node, (3|6);
    5 KB (662 words) - 19:09, 15 March 2013
  • PFV4 program script
    % 4-node, 6-DOF/node, C1,quartic-derived rectangular stream function ndof = eu.nndofs; % nndofs = number of velocity dofs per node, (6);
    16 KB (2,250 words) - 19:03, 15 March 2013
  • Code: Lid-driven cavity using pressure-free velocity form (2)
    ...re are a modified form of one due to Gopapacharyulu [1][2] and Watkins [5][6]. These quartic-complete elements have 24 degrees-of-freedom, six degrees-o % 4-node, 6-DOF/node, C1,quartic-derived rectangular stream function
    12 KB (1,673 words) - 20:07, 15 March 2013
  • PFV4 convection matrix
    % functions with 3, 4, or 6 degrees-of-freedom and defined on a % The columns of the array Vdof must contain the 3, 4, or 6 nodal
    6 KB (856 words) - 19:12, 15 March 2013
  • PFV4 get pressure
    nvd = eu.nndofs; % number of velocity DOFs at nodes (3|4|6); nvd = eu.nndofs; % number of velocity DOFs at nodes (3|4|6);
    11 KB (1,613 words) - 19:29, 15 March 2013
  • PFV diffusion matrix 2
    % functions on 4-node rectangular elements with 6 DOF per node using nd = 6; nd4=4*nd; ND=1:nd; % nd = number of dofs per node,
    5 KB (766 words) - 18:32, 4 July 2011
  • PFV convection matrix 2
    % basis functions on 4-node straight-sided quadrilateral elements with 6 DOF nd = 6; nd4=4*nd; ND=1:nd; % nd = number of dofs per node,
    7 KB (1,099 words) - 18:38, 4 July 2011
  • Pfv lid driven cavity
    GMRES.MaxRestarts=6; 1.e-8,1.e-7,1.e-6,1.e-5,5.e-5,1.e-4,2.5e-4,5.e-4,1.e-3,1.5e-3,3.e-3];
    13 KB (1,841 words) - 03:26, 29 June 2011
  • PFV diffusion matrix
    % functions with 3, 4, or 6 degrees-of-freedom and defined on a nndofs = eu.nndofs; % nndofs = number of dofs per node, (3|6);
    5 KB (670 words) - 15:58, 15 March 2013
  • PFV convection matrix
    % functions with 3, 4, or 6 degrees-of-freedom and defined on a % The columns of the array Vdof must contain the 3, 4, or 6 nodal
    6 KB (865 words) - 16:06, 15 March 2013
  • PFV get pressure
    nvd = eu.nndofs; % number of velocity DOFs at nodes (3|4|6); nvd = eu.nndofs; % number of velocity DOFs at nodes (3|4|6);
    11 KB (1,623 words) - 16:10, 15 March 2013
  • PFV program script
    GM.MRstrt=6; -1.e-7,-1.e-10,1.e-8,1.e-7,1.e-6,1.e-5,5.e-5,1.e-4,2.5e-4, ...
    15 KB (2,038 words) - 17:08, 15 March 2013
  • PFV quadature rules
    case 6 % degree 11
    2 KB (125 words) - 16:51, 15 March 2013
  • PFV GMRES solver
    % DropTol - drop tolerance for luinc preconditioner (default=1e-6). % Drop tolerance for luinc preconditioner, nominal value - 1.e-6
    5 KB (689 words) - 04:10, 29 June 2011
  • PFV get pressure 2
    nd = 6; ND=1:nd; % Number DOFs in velocity fns (bicubic-derived) GMRES.MaxRestarts=6;
    19 KB (3,020 words) - 18:42, 4 July 2011
  • Code: Thermal cavity using pressure-free velocity form
    ...re are a modified form of one due to Gopapacharyulu [1][2] and Watkins [5][6]. These quartic-complete elements have 24 degrees-of-freedom, six degrees-o ...forming rectangular plate element | rest = Int. J. Numer. Meth. Fluids, '''6''': 305-308}}
    14 KB (1,998 words) - 21:21, 15 March 2013
  • PFV Tconvection matrix 2
    % Uses 4-node quartic velocity functions with 6 dof per node. nV = 6; nfV = nnd*nV; % nV = number of V dofs per node, nfV = number V dofs.
    7 KB (1,061 words) - 16:13, 7 July 2011
  • PFV Buoyancy matrix 2
    % weights on 4-node rectangular elements with 6 DOF per node nV = 6; nfV = nnd*nV; % nV = number of V dofs per node, nfV = number V dofs.
    6 KB (874 words) - 16:20, 7 July 2011
  • Code: Quadrature on Tetrahedra
    ...0000000000000, 0.2500000000000000, 0.2500000000000000, 0.2500000000000000]/6; ...0000000000000, 0.4500000000000000, 0.4500000000000000, 0.4500000000000000]/6;
    5 KB (116 words) - 21:13, 7 November 2016
  • Code: 3D Lid-driven cavity using pressure-free velocity form
    nd = 6; nd2=nd*nd; % Number DOFs per node. DO NOT CHANGE! ni=0; nf=0; dnf=6; nt=1;
    24 KB (3,584 words) - 14:08, 10 August 2011
  • PFV 3D diffusion matrix
    % functions on 8-node rectangular hexahedral elements with 6 DOF per node ndfn=6; % number of degrees of freedom per node.
    5 KB (815 words) - 12:17, 20 July 2011

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