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• Introduction to turbulence/Reynolds averaged equations
  </td><td width="5%">(6)</td></tr></table> <font color="orange" size="3">Figure 3.6 not uploaded yet</font>
  45 KB (7,578 words) - 08:35, 21 August 2013
• Flow around a circular cylinder
  [6] Dennis, S. C. R. and Chang, G.-Z., 1970, Numerical solutions for steady fl ... turbulence models // J. Engineering Physics and Thermophysics. Vol.78. No.6. pp. 1199-2013.
  6 KB (884 words) - 11:31, 8 April 2017
• Introduction to turbulence/Turbulence kinetic energy
  </td><td width="5%">(6)</td></tr></table> ...xtra assumptions about the last term. It is only the last term in equation 6 that can be identified as the true rate of dissipation of turbulence kineti
  47 KB (7,664 words) - 12:47, 13 December 2013
• Tdyn
  ...te calculus-finite element formulation|rest=Int. Jnl. Num. Meth. Fluids 54(6-8): 609-637}}
  3 KB (388 words) - 09:14, 3 January 2012
• Stratford's separation criterion
  C'_p \cdot \sqrt{x' \frac{dC'_p}{dx}} = k \cdot \left( \frac{Re}{10^6} \right) ^ {0.1}
  3 KB (543 words) - 11:10, 11 December 2013
• Introduction to turbulence/Homogeneous turbulence
  Figure 6.1 shows an attempt to correlate some of the grid turbulence data using the ...el too comfortable about this, let's look at another curve shown in figure 6.2. This one is also due to Sreenivasan, but a compiled a decade later and b
  10 KB (1,751 words) - 13:03, 21 March 2012
• Introduction to turbulence/Free turbulent shear flows
  ...shear flows have in common with the homogeneous flows discussed in Chapter 6 is that their scales continue to grow as long as the flow remains turbulent </td><td width="5%">(6)</td></tr></table>
  67 KB (11,204 words) - 13:42, 19 April 2016
• Main Cavity.f90 - Main modul
  x_exct(6)=0.1563 ; v_exct(6)= 0.37095 y_exct(6)=0.1719 ; u_exct(6)=-0.38289
  7 KB (885 words) - 14:54, 19 May 2016
• Introduction to turbulence/Wall bounded turbulent flows
  </td><td width="5%">(6)</td></tr></table>
  41 KB (7,002 words) - 13:02, 21 March 2012
• PFV4 diffusion matrix
  % functions with 3, 4, or 6 degrees-of-freedom and defined on a nndofs = eu.nndofs; % nndofs = number of dofs per node, (3|6);
  5 KB (662 words) - 19:09, 15 March 2013
• PFV4 program script
  % 4-node, 6-DOF/node, C1,quartic-derived rectangular stream function ndof = eu.nndofs; % nndofs = number of velocity dofs per node, (6);
  16 KB (2,250 words) - 19:03, 15 March 2013
• Code: Lid-driven cavity using pressure-free velocity form (2)
  ...re are a modified form of one due to Gopapacharyulu [1][2] and Watkins [5][6]. These quartic-complete elements have 24 degrees-of-freedom, six degrees-o % 4-node, 6-DOF/node, C1,quartic-derived rectangular stream function
  12 KB (1,673 words) - 20:07, 15 March 2013
• PFV4 convection matrix
  % functions with 3, 4, or 6 degrees-of-freedom and defined on a % The columns of the array Vdof must contain the 3, 4, or 6 nodal
  6 KB (856 words) - 19:12, 15 March 2013
• PFV4 get pressure
  nvd = eu.nndofs; % number of velocity DOFs at nodes (3|4|6); nvd = eu.nndofs; % number of velocity DOFs at nodes (3|4|6);
  11 KB (1,613 words) - 19:29, 15 March 2013
• PFV diffusion matrix 2
  % functions on 4-node rectangular elements with 6 DOF per node using nd = 6; nd4=4*nd; ND=1:nd; % nd = number of dofs per node,
  5 KB (766 words) - 18:32, 4 July 2011
• PFV convection matrix 2
  % basis functions on 4-node straight-sided quadrilateral elements with 6 DOF nd = 6; nd4=4*nd; ND=1:nd; % nd = number of dofs per node,
  7 KB (1,099 words) - 18:38, 4 July 2011
• Pfv lid driven cavity
  GMRES.MaxRestarts=6; 1.e-8,1.e-7,1.e-6,1.e-5,5.e-5,1.e-4,2.5e-4,5.e-4,1.e-3,1.5e-3,3.e-3];
  13 KB (1,841 words) - 03:26, 29 June 2011
• PFV diffusion matrix
  % functions with 3, 4, or 6 degrees-of-freedom and defined on a nndofs = eu.nndofs; % nndofs = number of dofs per node, (3|6);
  5 KB (670 words) - 15:58, 15 March 2013
• PFV convection matrix
  % functions with 3, 4, or 6 degrees-of-freedom and defined on a % The columns of the array Vdof must contain the 3, 4, or 6 nodal
  6 KB (865 words) - 16:06, 15 March 2013
• PFV get pressure
  nvd = eu.nndofs; % number of velocity DOFs at nodes (3|4|6); nvd = eu.nndofs; % number of velocity DOFs at nodes (3|4|6);
  11 KB (1,623 words) - 16:10, 15 March 2013