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Sutherland law

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Revision as of 03:36, 20 October 2005

Sutherland's law for molecular viscosity coefficient is given by


\mu = \mu_{\mbox{ref}} \left( \frac{T}{T_{\mbox{ref}}} \right)^{3/2} \frac{ T_{\mbox{ref}} + T_s }{ T + T_s}

For air,

  • T_s = 110.6 K
  • T_{\mbox{ref}} = 273.15 K
  • \mu_{\mbox{ref}} = 1.716 \times 10^{-5} kg/(m-s)
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