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April 2, 2011, 16:18 |
RANS - time averaging?
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#1 |
New Member
Join Date: Apr 2011
Posts: 2
Rep Power: 0 |
Hi,
using the Reynolds-Averaged-Navier-Stokes (RANS), the air flow is averaged over a certain time t. What is the value of t for non-transient simulations? Maybe this quotation of the CCM+ user guide helps to understand my question: "To obtain the Reynolds-Averaged Navier-Stokes (RANS) equations, the Navier-Stokes equations for the instantaneous velocity and pressure fields are decomposed into a mean value and a fluctuating component. The averaging process may be thought of as time averaging for steady-state situations and ensemble averaging for repeatable transient situations. The resulting equations for the mean quantities are essentially identical to the original equations, except that an additional term now appears in the momentum transport equation." (S. 2109 Version 5.02) Thanks! Connor |
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April 5, 2011, 05:52 |
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#2 |
Senior Member
Join Date: Mar 2009
Posts: 260
Rep Power: 18 |
I think you understand the text incorrect - think about the "may be thought".
That's a text for non-geeks |
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Tags |
rans, time, time average |
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