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March 9, 2011, 03:49 |
question about unsteady run and swirl number
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#1 |
Member
Ahmet
Join Date: Mar 2011
Location: Ankara/ Turkey
Posts: 37
Rep Power: 15 |
i have a case about unsteady flow. mesh has approximately 750.000 cells. but i don' t know what the time step must be? how can i calculate the time step? What is the relation between time step and cells. and second question: how can i calculate swirl number; i found that SN= G_theta/R.G_x. but i could not find how to calculate G_theta and G_x.
best regards, Ahmet. |
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March 14, 2011, 04:00 |
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#2 |
Senior Member
Join Date: Jun 2009
Posts: 100
Rep Power: 17 |
A general rule of thumb is to use a time step which is 1/100 th of the approximate time required for the flow to traverse the entirety of the CV.
If you see that the solution is taking a large number of iterations to converge you might consider using half of the initial time step and so on. |
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