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Calculating surface area in Axisymmetric simulation |
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April 16, 2014, 07:49 |
Calculating surface area in Axisymmetric simulation
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#1 |
Senior Member
Chaotic Water
Join Date: Jul 2012
Location: Elgrin Fau
Posts: 438
Rep Power: 18 |
Hi
I have a simple axisymmetric simulation: cylinder with ends as inlet and outlet - and an additional inlet that is a separated part of side cylinder surface, just a winded rectangle it would be in 3D. No problems converting to 2D, setting Axis boundary condition. Cylinder has R = 0.25 m and additional inlet has length of l = 0.05 m; so Inlet Area should be S1=Pi*R^2 and additional inlet area should be S2=2*Pi*R*l; their ratio S1/S2 = 2.5 I'm still confused on how Area is computed in Axisymmetric case: Report (no matter - Sum of Area on surface or Surface Integral of Field Function with Definition set to "1") returns S1 = 3.125E-2 m^2 and S2 = 1.25E-2 m^2. These values have the same ratio of 2.5. If i get it right - surface is calculated not for angle of 2*Pi, but for angle of 1 rad. Has anyone got any ideas of whether i understand thing right and .. why the hell is it 1 rad - not 2*Pi? |
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April 16, 2014, 15:09 |
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#2 |
New Member
Philhellene Ithaca
Join Date: Mar 2014
Posts: 10
Rep Power: 12 |
For asysymetrical calculations, effectively, STAR-CCM+ assumes the non-resolved dimension to be 1 rad. (For 2D cases, 1 m).
I suppose they preferred to strictly use 1 SI (m) or 1 SI derived (rad) unit. |
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February 16, 2022, 09:51 |
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#3 | |
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sina
Join Date: Nov 2021
Posts: 41
Rep Power: 5 |
Quote:
I want to compute the area in 2D axisymmetric that fluent use for computational , Does it obtain from pi*r^2? Best Regards, |
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