CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > Software User Forums > Siemens

why this boundary condition works?

Register Blogs Community New Posts Updated Threads Search

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   November 25, 2005, 01:26
Default why this boundary condition works?
  #1
manish
Guest
 
Posts: n/a
I have read manual that when we apply mass flow or velocity at inlet and pressure at outlet then it will more robust.but when we apply pressure at inlet and velocity at outlet it will diverge the solution.The later is applicable only to compressible flow.Can anybody tell me why this is happening? the outlet mass flow is applicable to fully developed flow.so what is fully developed flow? and why it is robust for outer mass flow? Thanx
  Reply With Quote

Old   November 26, 2005, 01:55
Default Re: why this boundary condition works?
  #2
DB
Guest
 
Posts: n/a
From basic PDE classification compressible flow equations are hyperbolic in nature and requires upwind differencing schemes for solution ie property(velocity etc) at any point in the domain is determined by the points upstream of the flow. Hence when you fix velocity at the exit you will be fixing the property of a downstream point which is to determined from the upstream points to model the physics of the problem correctly. Remember in starcd we use pressure correction schemes hence pressure field is determined from the velocity field. A fully developed flow is one in which flow profile does not change with distance. I hope this might help.

DB

  Reply With Quote

Old   November 26, 2005, 15:25
Default Re: why this boundary condition works?
  #3
manish
Guest
 
Posts: n/a
Thax DB.If mass flow remains same then can we say that it is a fully developed flow or not?The flow profile does not change with dist,so what u want to say?Can u tell me?
  Reply With Quote

Old   November 26, 2005, 22:22
Default Re: why this boundary condition works?
  #4
DB
Guest
 
Posts: n/a
Please look this site for more detail

http://instruct1.cit.cornell.edu/courses/fluent/pipe1/

For flow inside a pipe Laminar Re<2000 Transition 2000<Re<4000 Turbulent Re>4000
  Reply With Quote

Old   November 27, 2005, 10:00
Default Re: why this boundary condition works?
  #5
John Luo
Guest
 
Posts: n/a
Both conditions should work almost the same, if not, you should ask a new version.
  Reply With Quote

Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
why this boundary condition works? manish Fidelity CFD 1 January 4, 2006 04:27
why this boundary condition works? manish CFX 0 December 7, 2005 08:06
why this boundary condition works? manish Phoenics 1 November 30, 2005 06:20
why this boundary condition works? manish Main CFD Forum 1 November 26, 2005 15:22
why this type of boundary condition works? manish CFX 0 November 25, 2005 00:00


All times are GMT -4. The time now is 21:36.