CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > Software User Forums > OpenFOAM

basic question

Register Blogs Community New Posts Updated Threads Search

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   April 6, 2010, 14:47
Default basic question
  #1
Member
 
Axel Söhngen
Join Date: Jan 2010
Location: Germany, Trier
Posts: 31
Rep Power: 16
chelvistero is on a distinguished road
Hello, can anybody say me what output of pressure OpenFoam delivers? For example when I simulate a flow in side a pipe is the pressure in the pipe only the change of pressure or the change of pressure + atmospheric pressure or something else?

Thank you
chelvistero is offline   Reply With Quote

Old   April 6, 2010, 18:15
Default
  #2
Senior Member
 
Vesselin Krastev
Join Date: Jan 2010
Location: University of Tor Vergata, Rome
Posts: 368
Rep Power: 20
vkrastev is on a distinguished road
It depends of what kind of solver are you using. If it is an incompressible flow solver, the pressure output is the kinematic (p/rho) relative pressure, measured from an initial arbitrary reference value (which is not relevant for the flow solution). If it is a compressible one, the pressure output is the absolute effective pressure (p) in your domain, which has much more importance for your solution.
vkrastev is offline   Reply With Quote

Old   April 7, 2010, 05:21
Default
  #3
Member
 
Axel Söhngen
Join Date: Jan 2010
Location: Germany, Trier
Posts: 31
Rep Power: 16
chelvistero is on a distinguished road
Ok thank you that helps me!
chelvistero is offline   Reply With Quote

Old   April 7, 2010, 10:06
Default
  #4
Senior Member
 
Cean
Join Date: Feb 2010
Posts: 128
Rep Power: 16
shirazbj is on a distinguished road
Quote:
Originally Posted by vkrastev View Post
If it is an incompressible flow solver, the pressure output is the kinematic (p/rho) relative pressure, measured from an initial arbitrary reference value (which is not relevant for the flow solution).
I am trying to understand the p/rho output for potentialFoam cylinder sample. How could I get the relevent pressure field?

Thanks

Cean
shirazbj is offline   Reply With Quote

Old   April 7, 2010, 14:43
Default
  #5
Member
 
Axel Söhngen
Join Date: Jan 2010
Location: Germany, Trier
Posts: 31
Rep Power: 16
chelvistero is on a distinguished road
So is the pressure = p(reference) - p ?
chelvistero is offline   Reply With Quote

Old   April 8, 2010, 05:53
Default
  #6
Senior Member
 
Vesselin Krastev
Join Date: Jan 2010
Location: University of Tor Vergata, Rome
Posts: 368
Rep Power: 20
vkrastev is on a distinguished road
For the incompressible solvers the p/rho output is a difference between the calculated and the reference value: so, if the reference value is set to zero, an output of 10 means +10 m^2/s^2 measured from the reference and so on (for example, you can imagine that the zero value corresponds to the atmospheric p/rho value in standard conditions and then evaluate the effective pressure in your domain at the end of the calculations).
For the incompressible solvers you are forced to set realistic initial values of effective absolute pressure and temperature, because both of them influence the initial density (rho) value of the species contained in your domain. At the end of the calculation, the pressure output is exactly the absolute pressure (p, measured in Pa) in your domain.

Regards
vkrastev is offline   Reply With Quote

Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
[GAMBIT] Basic Question - Mesh Quality SheffieldStudent ANSYS Meshing & Geometry 8 December 15, 2010 18:24
basic question for pressure BC vivien OpenFOAM 0 November 23, 2009 06:01
Basic Poiseuille flow simulation question Ashish Main CFD Forum 0 October 2, 2007 14:05
New to CFD with some basic question Newbie Main CFD Forum 3 October 23, 2006 13:22
Basic LES question toyCFD Main CFD Forum 3 August 23, 2006 16:09


All times are GMT -4. The time now is 08:11.