[nileshjrane]

Hello All,

This is a basic question but just to clear the doubt once and for all:

The way we specify pressure for any compressible solver is with the units of [1 -1 -2 0..] i.e. p/rho. So we should specify the value of pressure as well after dividing p value by rho.

Meaning if i have p = 1MPa and rho = 10 kg/m3 then,

1) for compressible solver: p = 1/10 = 0.1
2) for incompressible solver: p = 10


Is this correct??

[bb_]

I think you confused things here.

For incompressible solvers, you have to specify the kinematic pressure, i.e. p/rho units [0 2 2 0 0 0 0] wheres as for compressible solvers, the actual pressure p [ 1 -1 -2 0 0 0 0 ] is used.

Therefore, for your case with p = 1MPa and rho = 10 kg/m3:

1) for compressible solver: p = 1 MPa = 1e6
2) for incompressible solver: p = 1e6/10 = 1e5

However, when running incompressible simulations, only pressure differences count so you could also use 0 as a reference pressure. If you want to obtain real pressure differences, multiply the result obtained with foam (kinematic pressure) with rho.

Hope that helps.

[nileshjrane]

Hi,

You are damn right.. i was indeed confuse . I realised my mistake but didnt get time to edit my post. In fact i realised that mentioning p/rho is the only way to specify density in incomressible solvers.

Thanks for the reply.