[zhangchuhan33]

Hi all,
Is there anybody to check what's the problem with this case? I provide the basic setup parameters of this case.

The terminal appears :
DILUPBiCG: Solving for Ux, Initial residual = 0.99000642, Final residual = 6.8541306e-08, No Iterations 4
DILUPBiCG: Solving for Uy, Initial residual = 0.99716613, Final residual = 6.9062653e-08, No Iterations 4
GAMG: Solving for p, Initial residual = 0.99962119, Final residual = 0.025839189, No Iterations 2
time step continuity errors : sum local = 0.93527788, global = 0.36717821, cumulative = 0.36824128
DILUPBiCG: Solving for thetaxx, Initial residual = 0.99220779, Final residual = 2.9157135e-07, No Iterations 3
DILUPBiCG: Solving for thetaxy, Initial residual = 0.98351029, Final residual = 1.6324874e-07, No Iterations 3
DILUPBiCG: Solving for thetayx, Initial residual = 0.98351029, Final residual = 1.6324874e-07, No Iterations 3
DILUPBiCG: Solving for thetayy, Initial residual = 0.92808389, Final residual = 1.7059121e-08, No Iterations 4
DILUPBiCG: Solving for thetazz, Initial residual = 0.048199694, Final residual = 2.7407462e-07, No Iterations 4
Recover Conformation Field

#0 Foam::error:rintStack(Foam::Ostream&) at ??:?
#1 Foam::sigFpe::sigHandler(int) at ??:?
#2 ? in "/lib/x86_64-linux-gnu/libc.so.6"
#3 ? in "/lib/x86_64-linux-gnu/libm.so.6"
#4 exp in "/lib/x86_64-linux-gnu/libm.so.6"
#5 Foam::exp(Foam::Field<double>&, Foam::UList<double> const&) at ??:?
#6 Foam::tmp<Foam::GeometricField<double, Foam::fvPatchField, Foam::volMesh> > Foam::exp<Foam::fvPatchField, Foam::volMesh>(Foam::tmp<Foam::GeometricField<doub le, Foam::fvPatchField, Foam::volMesh> > const&) at ??:?
#7 Foam::Oldroyd_B_L::correct() at ??:?
#8 ? at ??:?
#9 __libc_start_main in "/lib/x86_64-linux-gnu/libc.so.6"
#10 ? at ??:?
Floating point exception (core dumped)

These are boundary conditions of u and p
The u boundary condition is that
inlet
{
type fixedValue;
value uniform (1 0 0);
}

outlet
{
type zeroGradient;
}


wall
{
type fixedValue;
value uniform (0 0 0);
}

The p boundary condition is that
boundaryField
{


inlet
{
type zeroGradient;
}

outlet
{
type fixedValue;
value uniform 0;
}
wall
{
type zeroGradient;
}

There are some other information of this case
delta T 1e-4
mesh min volume 0.0029
inlet width 1
inlet velocity 1
This case is a very easy case to calculate the flow pattern of 2 dimensions of square tube . We give the inlet a rate of flow , use the pressure as the driven source .

Question:
What does that terminal appearance mean? What's wrong with this case?

Thank you all.