September 27, 2019, 12:45
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#21
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Senior Member
Andrew Somorjai
Join Date: May 2013
Posts: 175
Rep Power: 13
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Quote:
Originally Posted by Vishsel
Hi all,
In my case, i have to use a boundary type that needs the input as heat Flux, which is recalculated to get the output as temperature. my solver is chtMultiRegionSimpleFoam.
0/T file :
Code:
wall-mp-1
{
type externalWallHeatFluxTemperature;
heatSource flux;
q uniform 6000 ;
alphaEff alphaEff;
value uniform 323.15; ? //why i need to give temp. value ? because i already gave 'q' value know?
kappa solidThermo;
kappaName none;
}
Code:
Solving for fluid region fluid
DILUPBiCG: Solving for Ux, Initial residual = 0.00242038, Final residual = 2.85334e-005, No Iterations 1
DILUPBiCG: Solving for Uy, Initial residual = 0.00466735, Final residual = 7.31426e-005, No Iterations 1
DILUPBiCG: Solving for Uz, Initial residual = 0.00371143, Final residual = 0.00020355, No Iterations 1
DILUPBiCG: Solving for h, Initial residual = 0.00293122, Final residual = 0.000270902, No Iterations 1
Min/max T:323.3 323.3
GAMG: Solving for p_rgh, Initial residual = 0.0017874, Final residual = 1.12521e-005, No Iterations 3
time step continuity errors : sum local = 0.0587456, global = 0.00203603, cumulative = 10.1817
Min/max rho:***
DILUPBiCG: Solving for epsilon, Initial residual = 0.00358344, Final residual = 4.05951e-005, No Iterations 2
DILUPBiCG: Solving for k, Initial residual = 0.00331097, Final residual = 3.24722e-005, No Iterations 2
Solving for solid region solid
DICPCG: Solving for h, Initial residual = 0.00218476, Final residual = 9.17909e-006, No Iterations 4
Min/max T:min(T) [0 0 0 1 0 0 0] 323.129 max(T) [0 0 0 1 0 0 0] 349.782
ExecutionTime = 788.942 s ClockTime = 789 s
Why there is a need of two inputs as temp. value and heat flux value in 0/T ? Because i need to set an input as heat flux value only..
Is this boundary type is correct for assigning of heat flux as an input ? if it is not, Which one is suitable for my case?
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My guess would be that q is the heat flux but you still need the temperature as a reference to the outside. Q is nothing but the amount of watts/meter^2 but the temperature outside still needs to defined in order to determine how much gets transferred on the wall at a given rate???
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