second derivatives in the navier stokes equation -- CFD Online Discussion Forums

March 27, 2014, 10:32	second derivatives in the navier stokes equation	#1
catapult New Member Gregory Join Date: Nov 2010 Location: Dresden Posts: 14 Rep Power: 16	Dear all, I just have a quick question: are the second derivatives in the navier stokes equation symmetric? In other words: d/dx d/dy ux(x,y) = d/dy d/dx ux(x,y) ? where ux is the x-component of the fluid velocity. Thanks for your response!

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