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August 7, 2013, 14:57 |
Dimension of pressure: M/LT2 or L2/T2?
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#1 |
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Glenn Carlson, PE, PhD (ret)
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Sometimes the dimension of pressure is specified differently in 0/p file for different problems:
tutorials/basic/potentialFoam/cylinder dimensions [0 2 -2 0 0 0 0]; tutorials/compressible/rhoSimpleFoam/angledDuctExplicitFixedCoeff dimensions [1 -1 -2 0 0 0 0]; What tips me off to the correct dimension to use for a particular problem? Is there a general rule for the correct dimension of pressure in 0/p file? Is it simply a matter of whether the problem is 2D or 3D? Compressible or incompressible? I see that (M/LT2)/(M/L3) = L2/T2. Thanks. Last edited by gcengineer; August 7, 2013 at 14:59. Reason: Courtesy |
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August 7, 2013, 16:37 |
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#2 |
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Nima Samkhaniani
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one is pressure and the other one is pressure divide on density
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August 7, 2013, 16:44 |
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#3 |
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Glenn Carlson, PE, PhD (ret)
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Thank you, nimasam, for responding.
As I wrote, "I see that (M/LT2)/(M/L3) = L2/T2." What I want to know is why does one case require M/LT2, but another requires L2/T2? Is it 2D v 3D? Compressible v incompressible? Choice of solver? Last edited by gcengineer; August 7, 2013 at 16:45. Reason: Correction |
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August 7, 2013, 16:59 |
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#4 |
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Nima Samkhaniani
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you should check each solver , but its pressure on density in some incompressible solvers
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August 7, 2013, 17:24 |
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#5 |
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Glenn Carlson, PE, PhD (ret)
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It appears that the dimension of pressure is M/LT2 for compressible solvers and L2/T2 for incompressible solvers. Here, Boussinesq solvers are incompressible (e.g., buoyantBoussinesqSimpleFoam, buoyantBoussinesqPimpleFoam).
If there is an exception to this rule, I would appreciate knowing about it. Thanks. |
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August 7, 2013, 17:29 |
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#6 |
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Nima Samkhaniani
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forexample interFoam which is two-phase incompressible solver
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August 7, 2013, 17:41 |
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#7 |
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Glenn Carlson, PE, PhD (ret)
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Yes. However, for the cases in /tutorials/multiphase/interFoam, there is no 0/p, but 0/p_rgh has dimension M/LT2.
Thanks again. |
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