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LaunderGibson - turbulent viscosity in epsilon equation |
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November 14, 2012, 06:21 |
LaunderGibson - turbulent viscosity in epsilon equation
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#1 |
New Member
Join Date: Oct 2012
Posts: 3
Rep Power: 14 |
Hej
I'm inserting the LaunderGibson tubulence model to a two phase solver. Now I remarked that in LaunderGibson, in the transport equation for epsilon, a term DepsilonEff is used which contains the turbulent viscosity. Can someone explain why we have this viscosity? In my opinion, the great advantage of reynold stress models is the fact that we do not need the eddy viscosity assumption. So I'm a bit confused why there still is this turbulent viscosity... Thanks for help in advance Nik |
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March 31, 2015, 11:49 |
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#2 |
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Rakend D K
Join Date: Jul 2014
Posts: 3
Rep Power: 12 |
The Dissipation tensor in RST Model is assumed to be modeled by isotropy of small dissipative eddies.
where is the dissipation rate of turbulent kinetic energy. This is found from equation from model, where we model the transport of using turbulent viscosity Last edited by rakendd; March 31, 2015 at 20:27. |
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