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radialActuationDiskSource Thrust Distribution

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Old   November 13, 2020, 09:31
Exclamation radialActuationDiskSource Thrust Distribution
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Tom Waits
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Hi All,

In radialActuationDiskSource, the thrust is said to be distributed by

T(r) = T (C_0 + C_1 r^2 + C_2 r^4)

However in the code (see radialActuationDiskSourceTemplates.C) the thrust is actually distributed by:

T(r) = T (C_0 + C_1 r^2 + C_2 r^4) / (C_0 + C_1 R^2 / 2 + C_2 R^4 / 3)

where R = max(r)

Could anybody please let me know where the normalisation (denominator) of this thrust distribution comes from?

Many thanks in advance,

Tom Waits
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Old   November 13, 2020, 12:49
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Tom Waits
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Ok, I have understood now. The thrust is distributed over a circular region which gets you the denominator. Sorry for the premature question.
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