Problem with boundaryField and a scalar

FilipeDias93 · July 30, 2019, 12:33

Hello everyone!
I have recently noticed that my cases suddenly lost processor independency, i.e., the processor separations now affect the results. After some digging, I tracked it to an operation I have when updating the energy equation boundaryField. In it I have:

rhoE.boundaryField=(...)+rhoYh0.boundaryField();

In which rhoY0=rhoY1*h01+rhoy2*h02...

Where h01 is the formation enthalpy for species 1.

I tried to change the boundary update into:
rhoE.boundaryField=(...)+rhoY1.boundaryField()*h01 +rhoy2.boundaryField()*h02...

But when I compile, I receive an error stating that the operator * is not available between a geometricField and a dimensionedScalar. This only happens for the boundaryField, when updating the internalField this error does not appear.

I want to ask if there is a way that I can perform this operation.
Thank you kindly for your help

einstein_zee · July 31, 2019, 03:59

hey,

have you tried to multiply it with ds.value()? [ds = dimensionedScalar]

FilipeDias93 · July 31, 2019, 06:41

Good morning
That did work, thank you so very much!!

By the way, has anyone ever had problem with parallel independence due to boundary condition and internalField update?

Thank you very much for your help

July 30, 2019, 12:33	Problem with boundaryField and a scalar	#1
FilipeDias93 New Member Filipe Dias Join Date: Jul 2019 Posts: 6 Rep Power: 7	Hello everyone! I have recently noticed that my cases suddenly lost processor independency, i.e., the processor separations now affect the results. After some digging, I tracked it to an operation I have when updating the energy equation boundaryField. In it I have: rhoE.boundaryField=(...)+rhoYh0.boundaryField(); In which rhoY0=rhoY1h01+rhoy2h02... Where h01 is the formation enthalpy for species 1. I tried to change the boundary update into: rhoE.boundaryField=(...)+rhoY1.boundaryField()h01 +rhoy2.boundaryField()h02... But when I compile, I receive an error stating that the operator * is not available between a geometricField and a dimensionedScalar. This only happens for the boundaryField, when updating the internalField this error does not appear. I want to ask if there is a way that I can perform this operation. Thank you kindly for your help

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July 31, 2019, 03:59		#2
einstein_zee Member Hosein Join Date: Nov 2011 Location: Germany Posts: 93 Rep Power: 14	hey, have you tried to multiply it with ds.value()? [ds = dimensionedScalar]

July 31, 2019, 06:41		#3
FilipeDias93 New Member Filipe Dias Join Date: Jul 2019 Posts: 6 Rep Power: 7	Good morning That did work, thank you so very much!! By the way, has anyone ever had problem with parallel independence due to boundary condition and internalField update? Thank you very much for your help