CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > Software User Forums > OpenFOAM > OpenFOAM Programming & Development

rhoPorousSimpleFoam for modeling porous medium adiabatic flow

Register Blogs Community New Posts Updated Threads Search

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   August 17, 2014, 23:34
Default rhoPorousSimpleFoam for modeling porous medium adiabatic flow
  #1
New Member
 
zhiguo zhao
Join Date: May 2014
Posts: 1
Rep Power: 0
zhzhguo is on a distinguished road
Dear all,

I am using the standard solver rhoPorousSimpleFoam to model porous medium(catalyst converter) flow. I met one problem that I can not slolve. Hope anyone here give me some hints.

This is about adiabatic flow in one converter. The middle of the converter is catalyst, in which the flow is modeled with porous medium methodology.

I found that the outlet tempeature is increase by 20K compared with inlet temperature. But there is no energy input, all wall boundary is thermal adiabatic. When the flow resistance coef is decrease by 2 orders or there is no porous zone, results show temperature will not be increased. I summarize the question in one PPT file.

Any comments are appreciated. Thanks
zhzhguo is offline   Reply With Quote

Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
Flow through porous medium Kiran AS FLUENT 6 September 16, 2011 08:38
Modelling sound propagation through layered porous media nkinar Main CFD Forum 0 July 4, 2010 15:45
porous medium model, help please! cloudnqh FLUENT 0 February 26, 2010 15:27
air and sand flow through porous medium Thiyagarajan FLUENT 3 August 26, 2004 13:27
flow through a porous medium Vangelis Skaperdas Main CFD Forum 1 March 24, 1999 04:24


All times are GMT -4. The time now is 18:55.