[Siassei]

Hello,

I found under $FOAM_TUTORIALS/compressible/rhoPimpleFoam/RAS/angledDuctLTS/system/fvSolution following code.

    "(rho|U|h|k|epsilon|omega)"
    {
        solver          smoothSolver;
        smoother        symGaussSeidel;
        tolerance       1e-05;
        relTol          0.1;
    }

    "(rho|U|h|k|epsilon|omega)Final"
    {
        $U;
        tolerance       1e-05;
        relTol          0.1;
    }

My question is about the final statment and the $U; command.
Why U?
Is it the same as writing the *Final statement for each single variable? (rhoFinal, UFinal, ...)

[clapointe]

It means it is using the same solver/smoother as U.

Caelan

[mm66]

Originally Posted by Siassei

Hello,

I found under $FOAM_TUTORIALS/compressible/rhoPimpleFoam/RAS/angledDuctLTS/system/fvSolution following code.

    "(rho|U|h|k|epsilon|omega)"
    {
        solver          smoothSolver;
        smoother        symGaussSeidel;
        tolerance       1e-05;
        relTol          0.1;
    }

    "(rho|U|h|k|epsilon|omega)Final"
    {
        $U;
        tolerance       1e-05;
        relTol          0.1;
    }

My question is about the final statment and the $U; command.
Why U?
Is it the same as writing the *Final statement for each single variable? (rhoFinal, UFinal, ...)

But this part (i.e. "Final") does not affect the solver as what has been specified for "Final" is exactly the same as the rest of the iterations (similar tolerance and relTol values). In other words, there is no need for such definition if the conditions are going to be exactly the same (hope it was clear )...