Sectional force coefficients

tfuwa · October 7, 2011, 00:45

Greetings to all,

For Bluff Structures, OF has the excellent forceCoeffs utilities to calculate force coefficients, which are defined as drag coefficient Cd = Fx/(rho*U^2*D*H/2) and lift coefficient Cl = Fy/(rho*U^2*D*H/2). These are actually the averaged force cofficients along the bluff body. Sometimes, we need to know the sectional force coefficients at a certain cross-section along z-direction, which can be formulated as Cd(z) = Fd(z)/(rho*U^2*D/2) and Cl(z) = Fl(z)/(rho*U^2*D/2). They are obtained by integrating the pressure and shear stress over the circumference of a cross section.

Are these calculations for sectional force coefficients available in OF? The answer is probably no. Then, can anybody please suggest a way on programming to realize this utility? (I am not familiar with C++,

, so please give a little bit more information.)

Cheers,
Albert

kkpal · June 27, 2013, 07:49

hi albert, I'm facing the same problem, have you found the solution to this question?

October 7, 2011, 00:45	Sectional force coefficients	#1
tfuwa Member Albert Tong Join Date: Dec 2010 Location: Perth, WA, Australia Posts: 76 Blog Entries: 1 Rep Power: 15	Greetings to all, For Bluff Structures, OF has the excellent forceCoeffs utilities to calculate force coefficients, which are defined as drag coefficient Cd = Fx/(rhoU^2DH/2) and lift coefficient Cl = Fy/(rhoU^2DH/2). These are actually the averaged force cofficients along the bluff body. Sometimes, we need to know the sectional force coefficients at a certain cross-section along z-direction, which can be formulated as Cd(z) = Fd(z)/(rhoU^2D/2) and Cl(z) = Fl(z)/(rhoU^2D/2). They are obtained by integrating the pressure and shear stress over the circumference of a cross section. Are these calculations for sectional force coefficients available in OF? The answer is probably no. Then, can anybody please suggest a way on programming to realize this utility? (I am not familiar with C++, , so please give a little bit more information.) Cheers, Albert

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June 27, 2013, 07:49		#2
kkpal Senior Member Join Date: Jan 2013 Posts: 135 Rep Power: 13	hi albert, I'm facing the same problem, have you found the solution to this question?