|
[Sponsors] |
Relaltionship between pressure drop and drag force |
|
LinkBack | Thread Tools | Search this Thread | Display Modes |
April 7, 2005, 23:14 |
Relaltionship between pressure drop and drag force
|
#1 |
Guest
Posts: n/a
|
Hi,
I am simulation flow across a tube bank. Based on force balance in a closed system, the pressure drop per row of tubes and the total drag force (sum of friction and form drag) per ros should have the relationship of: DeltaP*A_T=Drag force Where A_T is the minimum transverse flow area between tubes. Am I right? I found my simulation results do not agree with this. Can anyone help me? Thank you very much. Li |
|
April 12, 2005, 10:57 |
Re: Relaltionship between pressure drop and drag f
|
#2 |
Guest
Posts: n/a
|
dP*S=drag force*L
|
|
April 12, 2005, 21:27 |
Re: Relaltionship between pressure drop and drag f
|
#3 |
Guest
Posts: n/a
|
Alex, Can you explain the S and L in your equation? It seems that the left hand side is a force (if s is a distance) and the right hand side is energy. What is the equation based on? Thank you for your help. Zhihua
|
|
April 13, 2005, 04:12 |
Re: Relaltionship between pressure drop and drag f
|
#4 |
Guest
Posts: n/a
|
Li,
We are also doing simulations based on tube banks resistance (using correlations by Zukauskas), so I would like to help, but am not clear about your tratment. Are you simulating the detailed flow, i.e., resolving each tube neighborhood by many cells or using a porous medium approach (the latter is our approach)? In the first approach the drag force arises naturally as the net normal-to-the-tubes force. In the latter, you usually model the pressure gradient, and from that - calculate the drag force per REV (Representative Elementary Volume). This volume is usually given by Sx*Sy*L, where Sx and Sy are the pitches of the tube array in both directions and L is the tube length. If you wish, I would send you an extract of a detailed description of the model we use. I hope this helps. |
|
April 13, 2005, 12:01 |
Re: Relaltionship between pressure drop and drag f
|
#5 |
Guest
Posts: n/a
|
Hi Rami,
I am using a periodic boundary condition to simulate the flow field at the inner rows of a tube bank, i.e., the fully developed region. The pressure drop per row of tubes is equal to the linear pressure gradient times the longitudinal distance. The drag force can be calculated based on the integration of pressur force/wall shear stress around a tube. My calculated Eu based on the pressure drop per row fits Zukauskas correlation very well (10% difference). Because the pressure drop is caused by drag, I tried to relate my pressure drop with the drag force. My questions is: What is the relationship? Thank you very much! Zhihua |
|
March 4, 2017, 17:04 |
Hi
|
#6 |
New Member
soheil
Join Date: Mar 2017
Posts: 7
Rep Power: 9 |
Hi Li
I have a similar problem like you I want to know how to calculate pressure drop per row of tube please help me thanks |
|
|
|
Similar Threads | ||||
Thread | Thread Starter | Forum | Replies | Last Post |
hydrodynamic drag and pressure drop of subchannels | chenxi05 | Main CFD Forum | 0 | June 24, 2011 13:37 |
Setup/monitor points of pressure and force coefficients | siw | CFX | 3 | October 22, 2010 07:07 |
Pressure drop of valve with valve opening of 30% | elogesh | Main CFD Forum | 2 | January 5, 2007 13:30 |
Pressure Drag not calculated correctly in CFX-Post | Andy | CFX | 5 | August 2, 2006 13:06 |
Pressure drop and flow drag | Li | FLUENT | 6 | April 23, 2005 14:33 |