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July 26, 2002, 14:58 |
Sutherland's Law - Helium
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#1 |
Guest
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Hi,
I was wondering if someone knew the constant in the Sutherland's relation for Helium gas. Thanks in advance, Nashat |
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July 28, 2002, 03:58 |
Re: Sutherland's Law - Helium
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#2 |
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Hi Nashat,
I do not have exactly the data you ask for, but can suggest the following way to get it: o Data for He may be found in http://properties.nist.gov/SemiProp/Gases/He.html o Choose a reference temperature and its associated viscosity. o Assume a value for the missing parameters, S. o Use a least-squares curve fit to find the value of S that most closely follows the experimental data from NIST. I hope this helps. |
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July 28, 2002, 16:45 |
Re: Sutherland's Law - Helium
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#3 |
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I found the formula for the air:
nul=1.486*10e-6*(T^1.5)/(110.6+T) for the Helium shouldn't be far. Take a look at Schlichting or A. Walz. "Boundary Layers of flow and Temperature". M.I.T. Press. 1969 |
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July 29, 2002, 05:55 |
Re: Sutherland's Law - Helium
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#4 |
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Use Lennard-Jones potentials, more data available and more accurate
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July 29, 2002, 09:29 |
Re: Sutherland's Law - Helium
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#5 |
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Here are the constants of the Sutherland law for Helium :
mu0 = 3.93267e-5 T0 = 809 C0 = 147.2 Hope it helps someone. Alexandre Chatelain. PhD student - LES of Heat Transfer. CEA Grenoble - LEGI/Most Team - FRANCE. |
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July 29, 2002, 11:46 |
Re: Sutherland's Law - Helium
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#6 |
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Thanks a lot for your replies. I'll give the data from NIST a try. Thanks Rami.
Nash'at |
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