[zoey gao]

I am using steady state to calculate dpm model and have set the mass flow rate of the surface injection. But what I'm not sure about is how long the surface injection has been jetting after the steady state calculations are done? I.e. how many particles were ejected in total by the surface injection source. Thanks!

[narrownetherrack]

Originally Posted by zoey gao

I am using steady state to calculate dpm model and have set the mass flow rate of the surface injection. But what I'm not sure about is how long the surface injection has been jetting after the steady state calculations are done? I.e. how many particles were ejected in total by the surface injection source. Thanks!

To determine how long the surface injection has been jetting and the total number of particles ejected in a steady-state calculation using a Discrete Phase Model (DPM), you need to follow these steps:
- Understanding Mass Flow Rate and Injection Duration boxing random
- Calculate the Number of Particles Injected
- Determine the Equivalent Time
Example Calculation
Let's assume:

Mass flow rate (
𝑚
˙
m
˙
) = 0.01 kg/s
Mass of a single particle (
𝑚
𝑝
m
p
​
) = 1e-6 kg
Equivalent time (
𝑡
t) = 1000 seconds (as an example for calculation)
Using the formula:

𝑁
=
0.01
 
kg/s
×
1000
 
s
1
×
1
0
−
6
 
kg/particle
N=
1×10
−6
kg/particle
0.01kg/s×1000s
​


𝑁
=
10
 
kg
1
×
1
0
−
6
 
kg/particle
N=
1×10
−6
kg/particle
10kg
​


𝑁
=
10
×
1
0
6
 
particles
N=10×10
6
particles

𝑁
=
10
,
000
,
000
 
particles
N=10,000,000particles

[zoey gao]

Originally Posted by narrownetherrack

To determine how long the surface injection has been jetting and the total number of particles ejected in a steady-state calculation using a Discrete Phase Model (DPM), you need to follow these steps:
- Understanding Mass Flow Rate and Injection Duration boxing random
- Calculate the Number of Particles Injected
- Determine the Equivalent Time
Example Calculation
Let's assume:

Mass flow rate (
𝑚
˙
m
˙
) = 0.01 kg/s
Mass of a single particle (
𝑚
𝑝
m
p
​
) = 1e-6 kg
Equivalent time (
𝑡
t) = 1000 seconds (as an example for calculation)
Using the formula:

𝑁
=
0.01
 
kg/s
×
1000
 
s
1
×
1
0
−
6
 
kg/particle
N=
1×10
−6
kg/particle
0.01kg/s×1000s
​


𝑁
=
10
 
kg
1
×
1
0
−
6
 
kg/particle
N=
1×10
−6
kg/particle
10kg
​


𝑁
=
10
×
1
0
6
 
particles
N=10×10
6
particles

𝑁
=
10
,
000
,
000
 
particles
N=10,000,000particles

Thank you for your help, but I am not sure about the injection time as it is not required to be set in the surface injection settings during steady state calculation. And iterative calculation is controlled by residuals, so I don't know how much mass the ejected particles will have after the calculation is completed.