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December 18, 2023, 09:22 |
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#21 | |
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December 18, 2023, 09:34 |
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#22 |
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Physics/experience tells you that this flow is close to instability. Not fully unstable like in turbulence but at the edge of it.
Your numerical representation of this flow will certainly not be exact, especially with a low order code, but also because of bcs and initial conditions. Finally, as the equations are non linear and the solver math is discrete, even things like how you factor terms in an equations will potentially produce differences (imagine two fully different solvers). What happens then is that your numerical representation of the flow in the different cases falls on different sides of the stability edge. And more, one of the solvers actually introduces sufficient disturbances to let instability to kick in while the other doesn't. In my opinion, there is nothing more natural to observe in computational physics. It probably happens more than users are capable to understand... just think about different RANS models giving qualitatively different results, it is just the same issue. |
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December 18, 2023, 09:41 |
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#23 | |
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BTW, just curious, when we are talking about unsteadiness, what exactly are we referring to? In numerics wise, is the unsteadiness due to the small nonconservation in the cells, because of the for example separation or small vortices? |
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December 18, 2023, 09:57 |
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#24 | |
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I am also curious about the instability from CFD side. Aside from the "errors", is the instability in CFD brought by the small non-conservations in the cells, due to like vortices or separation? |
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December 18, 2023, 10:02 |
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#25 |
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Filippo Maria Denaro
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What do you mean for lack in conservation?? That makes no sense …
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December 18, 2023, 10:05 |
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#26 |
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December 18, 2023, 10:27 |
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#27 | |
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Now, for non conservative methods like finite differences, non conservation is just a numerical error (altough, in a sense, more disruptive). For conservative methods, the only non conservation allowed is the one arising from the non perfect convergence of the equations but, again, this is purely numerical. Also, do not confuse instability in CFD as in unstable numerical methods (say, too high CFL for explicit methods) with the dynamical instability I've been mentioning. The physical and numerical flow are two dynamical systems which, under certain conditions, become unstable. The closer is the numerical dynamical system to the physical one, the more the two will behave consistently. This is what I've been talking about. Unfortunately I can't explain here anything about dynamical systems or fluid dynamics in general, but you need to understand that before even try to perform unsteady CFD. In very rough terms, by instability we mean the sphere on the top of the hill kind of situation, but applied to the particles of a flow and the forces acting on them (the reference frame in fluid dynamics already makes the matter much more complex) If we now turn our attention to steady simulations, matter is slightly more complex, because the system evolution is not anymore along the paths allowed by the (numerical representation of the) physics, but otherwise everything we said kind of applies in a certain way. |
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December 18, 2023, 10:31 |
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#28 | |
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Filippo Maria Denaro
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The correct answer depend on the specific flow problem. |
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December 18, 2023, 11:01 |
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#29 | |
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The instability I am concerned about is more likely connected to the physical flow phenomena induced numerically "nonconservative". Some interpretations like: residuals start oscillating at some level in steady state, indicating instable flow characteristics (See the picture attached, snapshot from "Computational Methods for Fluid Dynamics" by Ferziger). In such a case, does this mean it is because the separation or vortices that prevent the residuals from dropping and, in other words, "bring in" the nonconservation and thus instabilities? |
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December 18, 2023, 11:10 |
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#30 |
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Filippo Maria Denaro
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No, you can get a steady state even if you have separation and vortices. The issue is if this state is stable or not under perturbations.
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December 18, 2023, 13:48 |
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#31 | |
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andy
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You refer to using the SIMPLE scheme for an unsteady simulation which raises the question how given SIMPLE is a steady scheme not an unsteady one? If a single pressure correction step is taken with some relaxation factors then the flowfield is not going to be a valid unsteady one regardless of whether vortices are shed or not. If the time derivative term is included and several SIMPLE-like inner iterations are performed then it is likely to be a valid unsteady flowfield but such a scheme would not normally referred to as SIMPLE. If a very fine grid is used so that the numerical errors are negligible then everything that is supposed to be conserved will be. If a normal reasonable grid is used then the numerical errors will be small and so will the conservation errors. However, numerical scheme can be arranged to strictly conserve a few physical quantities (not all obviously) when the equations are fully solved. Which physical quantities are strictly conserved varies from scheme to scheme with some opting to not strictly conserving anything. Which physical quantities are best conserved varies from problem to problem as does the best form for the numerical/discretization errors. In your case an optimum numerical scheme for a steady state solver is going to be rather suboptimal for an unsteady solver for vortices and vice-versa. The people behind STAR will know all this but quite what has been implemented and how/if/what can be changed via parameters is a task for those with an interest and access to the manuals. Unsteadiness is due to viscous forces being too weak to overcome inertial forces. If the numerical errors in the numerical scheme effectively strengthen the viscous forces a bit then that could be sufficient to prevent waviness growing in the boundary layer over the cylinder. It is also possible (and ought to be looked up) that the symmetrical steady solution is still stable at your Reynolds number unless significantly perturbed. |
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December 18, 2023, 14:18 |
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#32 | |
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Arjun
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Coupled solver adds more flux dissipation here it seems. The solution is effectively lower Re case then. This seems to be the case. |
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December 19, 2023, 00:33 |
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#33 |
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December 19, 2023, 02:45 |
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#34 | |
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Filippo Maria Denaro
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Then the imperfect level of convergence in iterative solvere, approssimate BCs, etc. |
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steady and unsteady state |
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