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First layer height of turbulent natural convection case ?

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Old   November 16, 2019, 08:42
Default First layer height of turbulent natural convection case ?
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Ahmed
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I am working on very simple turbulent natural convection ( Turbulent natural convection in a square cavity ) ... I searched to know how to get the first layer thickness near the wall and found the following :

1) y + = [( y * u_T ) / KINEMATIC VISCOSITY] , y+ = 1 for solving in viscous layer

But now I am lost how to get this u_T for the turbulent natural convection for vertical walls of a square cavity

Any help will be appreciated
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Old   November 17, 2019, 02:28
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The friction velocity is closely related to the wall shear stress which you normally don't know, unless you've solved the problem before. You just have to take your best guess.
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