First layer height of turbulent natural convection case ?

tahtawy · November 16, 2019, 07:42

I am working on very simple turbulent natural convection ( Turbulent natural convection in a square cavity ) ... I searched to know how to get the first layer thickness near the wall and found the following :

1) y + = [( y * u_T ) / KINEMATIC VISCOSITY] , y+ = 1 for solving in viscous layer

But now I am lost how to get this u_T for the turbulent natural convection for vertical walls of a square cavity

Any help will be appreciated

LuckyTran · November 17, 2019, 01:28

The friction velocity is closely related to the wall shear stress which you normally don't know, unless you've solved the problem before. You just have to take your best guess.

November 16, 2019, 07:42	First layer height of turbulent natural convection case ?	#1
tahtawy Member Ahmed Join Date: Sep 2019 Posts: 34 Rep Power: 7	I am working on very simple turbulent natural convection ( Turbulent natural convection in a square cavity ) ... I searched to know how to get the first layer thickness near the wall and found the following : 1) y + = [( y * u_T ) / KINEMATIC VISCOSITY] , y+ = 1 for solving in viscous layer But now I am lost how to get this u_T for the turbulent natural convection for vertical walls of a square cavity Any help will be appreciated

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November 17, 2019, 01:28		#2
LuckyTran Senior Member Lucky Join Date: Apr 2011 Location: Orlando, FL USA Posts: 5,743 Rep Power: 66	The friction velocity is closely related to the wall shear stress which you normally don't know, unless you've solved the problem before. You just have to take your best guess.