Equivalent of fully-developed boundary condition in polar coordinate

February 23, 2019, 07:33		#21
FMDenaro Senior Member Filippo Maria Denaro Join Date: Jul 2010 Posts: 6,849 Rep Power: 73	Again, you have all that is required...you can also write d/dx= d/dr dr/dx + d/dtheta dtheta/dx

February 23, 2019, 07:36

#22

mostanad

Senior Member

mohammad

Join Date: Sep 2015

Posts: 279

Rep Power: 12

Quote:

Originally Posted by FMDenaro

Again, you have all that is required...you can also write

d/dx= d/dr dr/dx + d/dtheta dtheta/dx

Please write the relation for only one time. What do you obtain at the end of this procedure? I want to compare it with my result.

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