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February 15, 2019, 12:05 |
Vorticity thickness in temporal mixing layer
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#1 |
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Hi!
I am struggling with calculating the vorticity thickness in temporal mixing layers. Which is defined as Where U_1 and U:2 are the lower and upper free stream velocities in opposite directions. A typical nondimensionalized velocity profile is U/U_1=tanh(y). To demonstrate the problem: A simple example is if U_1=1 and U_2=-1. The maximum gradient of tanh(y) is 1. Which yileds a vorticity thickness of 2. But I am supposed to get vorticity thickness of order 1e-4, based on a couple of papers, what am I doing wrong? |
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February 15, 2019, 12:07 |
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#2 |
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Vorticity thickness =(U_1-U_2) / (du/dy)_max
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February 15, 2019, 12:31 |
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#3 |
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Filippo Maria Denaro
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Are you working with dimensional or non-dimensional variables? The Reynolds number has the vorticity thickness as characteristic lenght, therefore in non-dimensional variables this thickness is O(1). |
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February 15, 2019, 12:47 |
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#4 | |
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Dimensional. For example, one paper claims to have vorticity Reynolds number of 100 with 0.2 mach, which for air is about 70 m/s. which gives a vorticity thickness of 140/70 which is 2. In order to fulfill reynolds number of 100 the viscosity has to be 0.35 which doesn't make any sense. 100=((U_1-U_2)*d)/vis vis=100/(140*2)=0.35 where d is viscosity thickness. |
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February 15, 2019, 12:50 |
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#5 | |
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Filippo Maria Denaro
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vorticity thickness of 2 meters???? |
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February 15, 2019, 12:59 |
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#6 |
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February 15, 2019, 13:20 |
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#7 | |
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Filippo Maria Denaro
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If you consider that U1=1m/s and U2=-1m/s and the initial velocity is u(y)= U1 * tan h (2*y/delta1) the derivative is du/dy = 2*U1 / (delta1 *cos h (2*y/delta1)) Therefore the delta1 value is the initial condition you have to prescribe. We did that in Sec.5.2.1 https://www.researchgate.net/publica...-uniform_grids |
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February 15, 2019, 13:36 |
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#8 | |
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Thank you, but what if the delta is the vorticity thickness? Which looks like the paper I read did? |
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February 15, 2019, 13:41 |
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#9 | |
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Filippo Maria Denaro
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But the vorticity thickness evolves starting from some initial condition... If you are interested in the temporal mixing you have to consider the evolution delta(t) but the thickness at t=0 is what you prescribe from your initial velocity profile |
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February 15, 2019, 13:47 |
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#10 |
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Ok thanks, so that means I can just reverse the calculations in order to find out what initial delta1 they used ?
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February 15, 2019, 14:51 |
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#11 |
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Filippo Maria Denaro
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February 15, 2019, 18:22 |
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#12 |
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February 15, 2019, 18:28 |
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#13 |
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Filippo Maria Denaro
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February 17, 2019, 11:36 |
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#14 |
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Thank you
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