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February 20, 2018, 13:58 |
Hyperbolic equation in conservative form
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#1 |
Senior Member
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say, for the most common hyperbolic equation
Let's be specific, say (it's the LWH traffic model) where the is a function of u, which is and the , u is the density of car flow. To solve this equation, of course I have to find out the CFL condition, but for the conservative form, the coefficient in front of convective term is 1 which means dt is bounded by 1; however it seems the "wave velocity" should be which aka phase velocity. But this requires to use the product rule of the derivative and it kind of like break the conservative form and it becomes , and now the velocity used for computing CFL should be v. But when actually solve this equation, should I back to the conservative form, or just stay with the one after product rule? And a more general question: for conservative form, how should I determine the CFL condition? What if I have a complex f(u) and not sure which one is the velocity I should use for CFL condition? Is it still the phase velocity I mentioned above? or is it something else? |
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February 20, 2018, 14:20 |
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#2 |
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Filippo Maria Denaro
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When you consider d/dx f(u) = df/du *du/dx you express the quasi-linear form of the conservation law
du/dt + f'(u) du/dx =0 Have a look to the traffic flow equation problem described in the book of Leveque (page 203). |
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February 20, 2018, 15:57 |
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#3 |
Senior Member
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Thx for the recommendation. I ran through the section, what I get is that, we can only determine the time step size by taking the quasi-linear form of hyperbolic equation; but when we are trying to solve the equation itself, we typically go back to the conservative form...
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February 20, 2018, 16:00 |
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#4 | |
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Filippo Maria Denaro
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Quote:
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February 20, 2018, 16:03 |
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#5 |
Senior Member
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February 20, 2018, 16:26 |
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#6 |
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Filippo Maria Denaro
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February 20, 2018, 16:31 |
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#7 |
Senior Member
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February 20, 2018, 22:51 |
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#8 |
Super Moderator
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Yes, f'(u) is the local wave speed.
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February 21, 2018, 04:40 |
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#9 |
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Filippo Maria Denaro
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