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Help regarding 1D compressible flow (Sod Shock tube) |
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August 25, 2022, 06:27 |
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#21 |
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Poly T
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the only correct response to „i need your codes“ is: I need your money.
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August 25, 2022, 11:04 |
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#22 |
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javeria
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how much money🤔
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August 25, 2022, 17:26 |
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#23 |
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Poly T
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I hope you realize this was a joke. Is this a homework problem?
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August 25, 2022, 17:53 |
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#24 |
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javeria
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no this is not my homework and I ask for help..
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August 25, 2022, 18:00 |
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#25 |
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Poly T
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well, post your code and we can have a look
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August 25, 2022, 18:02 |
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#26 |
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javeria
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I haven't any idea about high resolution scheme that how I do coding for it in MATLAB
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August 25, 2022, 18:06 |
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#27 |
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Poly T
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Then why do you want to code it ? First read up on the theory.
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August 25, 2022, 18:07 |
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#28 |
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javeria
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I read the literature but my coding is not too much strong
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August 26, 2022, 01:19 |
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#29 |
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Poly T
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then you should start with a simpler task. Show your work and we might help, but do not expect us to do the work for you.
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August 26, 2022, 17:21 |
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#30 |
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javeria
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ok sure I will share my code
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August 27, 2022, 07:42 |
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#31 |
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javeria
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clear all;
close all; clc; R=287; %Cv=717; gamma=1.4; rhol=1; Ul=0; Pl=100000; rhor=0.125; Ur=0; Pr=10000; c=50; delx=20/c; delt=.0004278; lambda=.001069; for i=1:1:c+1 x(i)=-10+(i-1)*delx; end for i=1:1:c+1 if (x(i)<0) rho(1,i)=rhol; u(1,i)=Ul; p(1,i)=Pl; else rho(1,i)=rhor; u(1,i)=Ur; p(1,i)=Pr; end end for i=1:1:c+1 mom(1,i)=rho(1,i)*u(1,i); %t(1,i)=p(1,i)/(rho(1,i)*R); e(1,i)=p(1,i)/((gamma-1)*rho(1,i)); energ(1,i)=(e(1,i)+.5*u(1,i)^2); energrho(1,i)=energ(1,i)*rho(1,i); end for n=2:1:30 for i=2:1:c rho(n,i)= .5*(rho(n-1,i-1)+ rho(n-1,i+1))-.5*lambda*(u(n-1,i+1)*rho(n-1,i+1)-u(n-1,i-1)*rho(n-1,i-1)); mom(n,i)= .5*(mom(n-1,i-1)+ mom(n-1,i+1))-.5*lambda*(u(n-1,i+1)*mom(n-1,i+1)+p(n-1,i+1)-p(n-1,i-1)-u(n-1,i-1)*mom(n-1,i-1)); energrho(n,i)= .5*(energrho(n-1,i-1)+energrho(n-1,i+1))-.5*lambda*((u(n-1,i+1)*energrho(n-1,i+1)+p(n-1,i+1)*u(n-1,i+1) - u(n-1,i-1)*energrho(n-1,i-1)+p(n-1,i-1)*u(n-1,i-1))); energ(n,i)=energrho(n,i)/rho(n,i); u(n,i)=mom(n,i)/rho(n,i); e(n,i)=energ(n,i)-.5*u(n,i)^2; %t(n,i)=e(n,i)/Cv; p(n,i)=(gamma-1)*rho(n,i)*e(n,i); end rho(n,1)=rho(1,1); rho(n,c+1)=rho(1,c+1); mom(n,1)=mom(1,1); mom(n,c+1)=mom(1,c+1); e(n,1)=e(1,1); e(n,c+1)=e(1,c+1); %t(n,1)=t(n,2); %t(n,1)=e(n,1)/Cv; %t(n,c+1)=t(n,c); %t(n,c+1)=e(n,c+1)/Cv; p(n,1)=p(1,1); %p(n,1)=rho(n,1)*R*t(n,1); p(n,c+1)=p(1,c+1); %p(n,c+1)=rho(n,c+1)*R*t(n,c+1); u(n,1)=u(1,1); %u(n,1)=mom(n,1)/rho(n,1); u(n,c+1)=u(1,c+1); %u(n,c+1)=mom(n,c+1)/rho(n,c+1); end t=plot(x,p(30,,'or'); axis([-10 10 0 100000]) t=plot(x,u(30,,'or'); axis([-10 10 -150 450]) t=plot(x,rho(25,,'or'); axis([-10 10 0 1.1]) |
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August 27, 2022, 07:43 |
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#32 |
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javeria
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i need the pressure, velocity and density plot but in this code not generate
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August 27, 2022, 07:57 |
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#33 |
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javeria
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and second this one
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August 27, 2022, 08:54 |
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#34 |
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Filippo Maria Denaro
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August 27, 2022, 16:25 |
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#35 |
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javeria
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i do not understand the python.. matlab please
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August 27, 2022, 16:36 |
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#36 |
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Poly T
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Honestly, dude, if you cannot figure out how to translate python into matlab or vice versa, you should stop trying to write cfd codes. No one here will spoon feed you. Stop this or put serious work into it. You come across as a whiny high school kid who wants others to do the homework for him. If you have a direct question, ask - but stop trying to leech.
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August 29, 2022, 05:47 |
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#37 |
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javeria
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I just asked for help so why you mind it. I am stuck I used maacormack, laxwendroff and roe's scheme. Now i need some other scheme to compare the results and submit my thesis. If you are not helping me ignore.
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August 29, 2022, 05:49 |
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#38 |
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Poly T
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I mind because you are not asking for help. You are asking „solve my problems for me because I am too lazy to even formulate a meaningful question“.
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August 29, 2022, 05:52 |
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#39 |
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javeria
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I asked to share someone matlab codes then i will make changes in it according to my problem
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August 29, 2022, 05:57 |
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#40 |
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javeria
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so please if someone can help me let me know. Because i will have submit my thesis also by tomorrow
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