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Use of CFD in which outlet condition is not known |
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October 5, 2015, 13:22 |
Use of CFD in which outlet condition is not known
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#1 |
Senior Member
sluzzer
Join Date: Jul 2014
Posts: 146
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Very late I observed that for every cfd simulation both the inlet and outlet condition should be known!
But in most cases outlet conditions are not known! I understood that there are 2 ways to address this problem: 1. Model till we know the outlet condition. Generally it will be till where it opened to atmospheric conditions. But often this will be very complicated because of geometry, mesh and computational effort 2. Assume a list of output conditions and develop the parameter of interest. For example, getting result of mass flow rate for different back pressure values. I don't know how to use this 2nd method to find the actual outlet condition! Can anybody please explain it? |
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October 5, 2015, 13:29 |
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#2 | |
Senior Member
Filippo Maria Denaro
Join Date: Jul 2010
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Quote:
the type of boundary conditions depends on the mathematical character of the model we are solving, then physical approximations dictate how to set them according to the type of the problem. For example, in supersonic flows (hyperbolic equation) you do not have to specify nothing at an outlet....on the other hand for incompressible flows the pressure equation is elliptic and BC.s must be specified also on an outlet |
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October 6, 2015, 10:07 |
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#3 |
Senior Member
Jonas T. Holdeman, Jr.
Join Date: Mar 2009
Location: Knoxville, Tennessee
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[QUOTE=shivasluzz;566618]Very late I observed that for every cfd simulation both the inlet and outlet condition should be known!
QUOTE] For incompressible flow, no output b.c. are needed if divergence-free (in the sense that integral div^2 u=0) finite elements are used. This might be referred to as open boundary conditions. See the paper: "A Hermite Finite Element Method for Incompressible Flow", IJNMF 64:376-408(2010). In fact, no input BC are needed either, other than specifying total flow, but the solution (fully-developed) is not very interesting. But then it could be argued that "no boundary condition" is a boundary condition. |
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October 6, 2015, 10:36 |
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#4 |
Senior Member
sluzzer
Join Date: Jul 2014
Posts: 146
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Thanks for the replies...
Suppose If I am analysing a centrifugal pump, then is it possible to get the outlet flow and pressure just by specifying the speed of rotation? I observed that in such analysis we need to specify the outlet flow or pressure! Suppose If I m using a pressure value at the outlet (involute outlet) then it's just an assumption rite and all other results are also not going to be the actual value! In mean in actual pumping system, there will be pipes and restrictions in the downstream stream of pump and those downstream components may create different backpressure in the actual case rite? |
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October 6, 2015, 11:43 |
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#5 | |
Senior Member
Filippo Maria Denaro
Join Date: Jul 2010
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Quote:
the speed of rotation is not sufficient to prescribe all the correct boundary conditions to have the mathematical problem well posed |
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October 6, 2015, 12:24 |
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#6 | |
Senior Member
Jonas T. Holdeman, Jr.
Join Date: Mar 2009
Location: Knoxville, Tennessee
Posts: 128
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Quote:
I think the point is that you are trying to model the external environment with a few operating parameters including inlet and outlet pressures which are indirectly related to the flow rate and viscous losses. I misunderstood your problem, which is distinct from the mathematical requirements to specify a solution to the problem. |
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