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Conjugate Heat Transfer - Contact temperature |
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February 25, 2015, 17:06 |
Conjugate Heat Transfer - Contact temperature
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#1 |
Member
Christian
Join Date: Sep 2013
Location: Germany
Posts: 88
Rep Power: 13 |
Hello everybody,
i'm wondering how a cfd software calculate conjugate heat transfer. Lets assume the following http://www.pic-upload.de/view-26247212/temp.png.html T_Boundary is on the far left set to 300 K If i know the contact temperature then the temperature everywhere in the solid can calculate with the fourier heat equation law and the temperature in the fluid can be calculated with the heat equation. But how will cfd calculate the contact temperature? Is it calculate by the energy equation with substitution of the contact temperature by the fourier law between the boundary and the contact area? How is this done with many elements? Regards Chris |
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February 25, 2015, 21:45 |
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#2 |
Senior Member
Michael Prinkey
Join Date: Mar 2009
Location: Pittsburgh PA
Posts: 363
Rep Power: 25 |
Conjugate heat transfer in CFD is normal done by meshing the solid and fluid zones. The temperature at the contact surface will not (necessarily) be ONE temperature. It will be a line (2D) or a surface (3D) of temperature corresponding to the solution of the heat transfer equation (2/3D Fourier law in the solid cells and Advection/Diffusion equation in the fluid cells).
If the solid is poorly conductive, you can reduce the solids to a simple BC for the fluid zone. But it is not possible to do that in general--usually because the solid regions often conduct heat very well and directly impact the temperature profile in the fluid zone. |
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February 26, 2015, 06:46 |
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#3 |
Member
Christian
Join Date: Sep 2013
Location: Germany
Posts: 88
Rep Power: 13 |
Thank you for your reply!
But im still wondering how at a discrete point the contact temperature is calculated. How are the fourier law and the advection equations coupled? Or is it just this way? http://www.pic-upload.de/view-26250491/temp.png.html And then the heatflow from the wall to the fluid is added in the energy equation of the navier stokes equations? If the temperature at the wall is calculated with the fourier law and the temperature of the fluid is calculated with the energy equation how the two temperatures (wall and fluid) are blanced in the next iteration step? Is just a heat source/sink applied to fourier and the energy equation? Last edited by Chris_321; February 26, 2015 at 09:00. |
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