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April 30, 2007, 16:54 |
Stabilizing Transient Source term
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#1 |
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I am solving a energy transport equation of the form
drhoH/dt + del.(rho V H) = -dP/dt+...+. in a collocated arrangement. I see that as the simulation progresses, the sources due to dp/dt is highly unstable. How can I stabilize my computation? The computation is for an incompressible flow but with heat transfer. -- CFDtoy |
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May 1, 2007, 11:37 |
Re: Stabilizing Transient Source term
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#2 |
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What kind of time-marching scheme do you use?.For multi-stage R-K it might be unclear how to discretize dp/dt on RHS.
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May 1, 2007, 12:16 |
Re: Stabilizing Transient Source term
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#3 |
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I am using a simple backward euler (implicit for stability!) Does any time splitting work?
CFDtoy |
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May 1, 2007, 13:02 |
Re: Stabilizing Transient Source term
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#4 |
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The stability analysis is based on linearized theories and hence you cannot necessarily guarantee stability for non linear problems.Did you check if explicit time marching worked for this particular case?
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May 1, 2007, 19:59 |
Re: Stabilizing Transient Source term
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#5 |
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explicit time stepping posed a lot of problems..since i hd problems in converging them.
normally when the source terms are not functions of the flw variables and cause such kind of stability problem..is there a way to reduce their propagation !>!? I am not aware of time splitting schmes for these purposes? anythin related? Thanks for your cmments harish. -- CFDtoy |
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May 1, 2007, 21:26 |
Re: Stabilizing Transient Source term
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#6 |
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I have never come across anything either.Is there any reason for using the equation for enthalpy instead of total energy or internal energy.Those equations do not have a time dependent pressure term and your implicit euler implementation might be easier.
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May 2, 2007, 09:27 |
Re: Stabilizing Transient Source term
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#7 |
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In case of total enthalpy, you do require the dp/dt term on the RHS. Also, finding temp using total enthalpy seemed easier.
CFDtoy |
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May 2, 2007, 10:15 |
Re: Stabilizing Transient Source term
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#8 |
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I think it would be the same even if you use the equation for internal energy.
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