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Transient features in steady state simulation? |
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October 9, 2013, 10:52 |
Transient features in steady state simulation?
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#1 |
Member
Adhikar Hariram
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Location: South Africa
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Hi All
In the case simulating flow with unsteady features, such as vortex shedding, using steady state simulation, will the results such as drag and lift co-efficients be valid? Would they essentially be the overall averaged values of the simulation or will the simulation need to be run as transient in order to get valid results? Your help is much appreciated Regards Adhikar |
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October 9, 2013, 12:11 |
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#2 | |
Senior Member
Filippo Maria Denaro
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Quote:
If the case admits no steady solution, a steady solver would simply not converge because the residual has a physical meaning that is the time-dependent part that balances all the fluxes. |
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October 9, 2013, 12:22 |
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#3 |
Member
Adhikar Hariram
Join Date: Dec 2012
Location: South Africa
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Hi Filippo
So essentially if I get residuals that aren't fluctuating, and eventually converge, then I have valid drag and lift coefficients? I am getting something along those lines however I also have a monitor for velocity in a point in space and this shows a fluctuating velocity with iterations, yet my drag and lift coefficient monitors seem to be converging to a constant value as well as my residuals. In short, I am seeing only fluctuating velocities yet all my other monitors appear to be converging, thus are my drag and lift coefficients? Thank you for your speedy response and any further help would be much appreciated. |
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October 9, 2013, 12:37 |
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#4 | |
Senior Member
Filippo Maria Denaro
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Quote:
However, laminar or turbulent flow model will drive to different meaning of the steady state. |
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October 9, 2013, 12:49 |
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#5 |
Member
Adhikar Hariram
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Thank you for your help, and from what I can gather I basically may need to run the simulation as transient in this case if I have constant residuals yet an unsteady flow. Maybe I can attach some images when the simulation is complete and you can provide some further knowledge. Many thanks for the help.
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October 9, 2013, 17:06 |
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#6 |
Senior Member
Joern Beilke
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A converged solution does not at all mean, that you get a physically correct result. Refine your mesh and see if you still get the same behaviour. Refine it probably even more. Run it transient and compare the lift and drag again.
Apart from this there might be lots of other reasons why the physics does not correspond to the numerics very well. |
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October 9, 2013, 17:18 |
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#7 | |
Senior Member
Filippo Maria Denaro
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Quote:
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October 10, 2013, 06:55 |
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#8 |
Member
Adhikar Hariram
Join Date: Dec 2012
Location: South Africa
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Hi, and thank you for the help. Moving forward I will certainly try your suggestions and see if it makes a difference, starting with the transient solution though as I am under some pressure for a result and this seems the most obvious first step forward. Thus far the simulation has finally complete and I have attached an image of the monitors I have in place in the case that you may provide further insight.
Many thanks for the help. |
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October 10, 2013, 06:56 |
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#9 |
Member
Adhikar Hariram
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If the image does does not display properly please right click it and open it in a new tab. Thanks
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October 10, 2013, 07:34 |
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#10 |
Senior Member
Filippo Maria Denaro
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your residuals clearly show that the solution will not converge towards a steady state. But, as I don't know details of your flow problem, I can not say if that indicates an unsteady solution or something is simply wrong in your setting.
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October 10, 2013, 07:50 |
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#11 |
Member
Adhikar Hariram
Join Date: Dec 2012
Location: South Africa
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Hi
My simulation is of flow over a heliostat at an angle of 30 degrees at a reynolds number of around 3x10^6. Seeing as the geometry is essentially two large, inclined flat plates that are in-line with each other, I have a strong feeling that the solution must be unsteady based on all the information you have provided. This especially so due to unsteady phenomena being associated with these kind of geometries. Thank you very much for your help, I think I can now move forward from this problem and simply have to deal with the turn-over time associated with transient simulation. |
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October 10, 2013, 07:54 |
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#12 | |
Senior Member
Filippo Maria Denaro
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Quote:
The pointwise solution is surely unsteady due to turbulence but the problem is to assess if your problem admits a statistically steady state to use RANS or has a statistically unsteady stato to use RANS. But, to tell the truth, I don't see a reason why you can not reach a statistical energy equilibrium and get a steady state ...the two plated are fixed not moving, right? |
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October 10, 2013, 08:04 |
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#13 |
Member
Adhikar Hariram
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Yes that's correct, the two plates are fixed in space.
So would you suggest then to also run the simulation as transient and to take an average of the results obtained via the transient simulation and compare them to the steady state solution in order to check if they are statistically valid? |
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October 10, 2013, 08:07 |
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#14 |
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Adhikar Hariram
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Thats the exact geometry, just to clear things up |
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October 10, 2013, 08:09 |
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#15 | |
Senior Member
Filippo Maria Denaro
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Quote:
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October 10, 2013, 08:12 |
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#16 |
Senior Member
Filippo Maria Denaro
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October 10, 2013, 08:17 |
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#17 |
Member
Adhikar Hariram
Join Date: Dec 2012
Location: South Africa
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Tags |
drag coefficients, lift, steady state, transient |
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